Answer:
On average, the scores of Class B are lower than Class A.
hope this helps
Step-by-step explanation:
Answer: no real solution
Thus, the function has no x- intercept
Step-by-step explanation:
Answer:
B) The heights of the bear should equal the class frequency.
Step-by-step explanation:
In drawing a histogram, the heights of the bear should equal the class frequency. as in histogram height of bar represent the frequency density and it´s area represent the frequency of class interval. Frequency distribution are represented by mean of rectangle. Earlier in the bar graph, width of bar does not represent any information, however, histogram´s bar width represent class interval.
Answer:
Miguel cabrera
Step-by-step explanation:
Given that :
Miguel cabrera's batting average = 0.33
Mike trout's batting average = 0.326
The average for both players was obtained during the same season:
Hence. Comparing their respective averages,
0.33 = 0.330
0.330 > 0.326
Hence, Miguel Cabrera's batting average is higher than that of Mike trout
360/6 = 60 degrees.
2pi/6 and pi/3 makes sense.
Out of 1/6 = 60 there's your answer.
Brainliest please!
