Find the product. (7x - 2y)(x + y) Enter the correct answer. DOU DONE Clear

The National Center for Health Statistics reported that of every 883 deaths in recent years, 24 resulted from an automobile acci

VARVARA [1.3K]

Answer:

There is a 2.7% chance that a particular death is due to an automobile accident?

Step-by-step explanation:

Automobile _____ 24 deaths

Cancer _________182 deaths

Heart disease ____333 deaths

Total ___________ 883 deaths

Probability = number of automobile accident deaths / total deaths

Probability = 24 / 883

Probability = 0.027

Probability = 2.7%

3 0

3 years ago

What is the weight, in Newtons, of a person on Earth whose mass is 90 kilograms? Gravity near the Earth's surface is 9.8 m/s2.

valentinak56 [21]

Answer:

W = 882 N

Step-by-step explanation:

Given that,

The weight of a person, W = 90 kg

The value of acceleration due to gravity, g = 9.8 m/s²

We need to find the weight of the person on Earth. The formula for the weight of an object is given by :

W = mg

Substitute all the values,

W = 90 kg × 9.8 m/s²

W = 882 N

So, the weight of the person is equal to 882 N.

8 0

3 years ago

What is the surface area of the prism?

kow [346]

$The\ surface\ area:A_s=2B+(S_1+S_2+S_3)\cdot H\\B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\S_1=5yd;\ S_2=12yd;\ S_3=13yd;\ h=8yd\\\\therefore\\\\A_s=2\cdot30+(5+12+13)\cdot8=60+30\cdot8=60+240=\boxed{300\ (yd^2)}$ $Volume\ of\ the\ prism:V=B\cdot H\\\\B\ (base)\ it's\ a\ right\ triangle:B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\H=8yd\\\\therefore\\\\V=30\cdot8=\boxed{240\ (yd^2)}\leftarrow\boxed{C}$

8 0

3 years ago

Read 2 more answers

Solve. Answer with a number only. -2/5(x+6)=10

malfutka [58]

Answer:

x= -31

Step-by-step explanation:

3 0

2 years ago

4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B

AleksAgata [21]

Answer:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

$\hat p=\frac{63}{200}=0.315$ estimated proportion of lawyers had used some form of advertising for their business

$p_o=0.25$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

8 0

3 years ago