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Strike441 [17]
2 years ago
12

If a die is rolled one time, find the probability of getting a six. P(6) = ?

Mathematics
2 answers:
elena-s [515]2 years ago
7 0

Answer:   \;\;\frac{1}{6} , \;\; 0.16667,\;\; \text{or about}\;\;17\%

Step-by-step explanation:

   A regular dice has 6 sides, and only one of those sides side has a six.

        We write probability as;

   \displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} = \frac{\text{number of times six is on the dice}}{\text{number of numberss on the dice}} =\frac{1}{6}

sergejj [24]2 years ago
5 0

Hi, there!

 _______

\boxed{\boxed{\sf{Probability=\dfrac{Favorable \ Outcomes}{Total \ Outcomes}}}}

Here,

<em>»</em> Favourable Outcome(s) -> getting a 6 on a die (1 outcome),  because only one side of a die has a six on it

<em>» </em>Total Outcomes -> 6 (you can only get 1, 2, 3, 4, 5, 6 if you roll one die)

So,

\sf{Probability_{(6)}=\dfrac{1}{6}}

Hope the answer - and explanation - made sense to you,

happy studying!!

                                                                                                        \tiny\textit{frozen \ melody}

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write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator. 40 to 56
masha68 [24]

Answer:

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Step-by-step explanation:

A common factor of 8 can be canceled from numerator and denominator.

  40/56 = (5·8)/(7·8) = (5/7)·(8/8) = (5/7)·1 = 5/7

_____

Since you know your multiplication tables, you know that 40 and 56 are both multiples of 8.

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If you don't know your multiplication tables, you can find the greatest common divisor (GCD) of the two numbers and divide each by that. The GCD can be found using Euclid's algorithm. For that, you divide the larger by the smaller and use the remainder as the new smaller number. The original smaller number is now the larger number. For these numbers, that looks like ...

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Now, your fraction is ...

  (40/8) / (56/8) = 5/7

3 0
3 years ago
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Hey mate.....

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This is ur answer....

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