Answer:
1.) 1 1/3 or 4/3
2.) 6
3.) 8
Step-by-step explanation:
Function composition substitutes more than just values or constants. It substitutes functions inside another function. Solve each expression by starting inner most and working to outermost.
1.) f(g(0)) = 1 1/3
Let g(x)=3x+2 and f(x)= x-2/3.
Begin with g(0) = 3(0) + 2 = 2.
Substitute x = 2 into f(x).
f(2) = (2) - 2/3 = 1 1/3
2.) g(f(2)) = 6
Let g(x)=3x+2 and f(x)= x-2/3.
Begin with f(2) = 2 - 2/3 = 1 1/3.
Substitute x = 1 1/3 into g(x).
g(1 1/3) = 3( 1 1/3) + 2 = 3(4/3) + 2 = 4 + 2 = 6
3.) g(g((0))
Let g(x)=3x+2.
Begin with g(0) = 3(0) + 2 = 2.
Substitute x = 2 into g(x).
g(2) = 3(2) + 2 = 8
Answer: river c = is 3260 river d =2260
Step-by-step explanation:
5520/2=2760
2760 2760
-500 +500
______________________
2260 + 3260 = 5520
Answer:
the 4th it hits 10 after 2 seconds
Step-by-step explanation:
the ball starts at (6,0) feet/height 0 seconds, then is thrown, at the slope/ top is where the ball accelerated or went the highest is (10,2) ten feet, two seconds, and was able to stay in the air for 6 and ends at (0,6 1/8) 0 feet and 6 1/8 seconds, that is why the the slope curves down, showing that the ball has landed but this is not exactly 6 seconds. hope this helps
y = -1 + 3/8x
2x - 5y = 6
Substitute the first equation into the second equation, since y is already by itself.
2x - 5(-1 + 3/8x) = 6
2x + 5 - 15/8x = 6
2x - 15/8x = 1
16/8x - 15/8x = 1
1/8x = 1 Multiply 8 on both sides to get x by itself
x = 8
Plug x into either of the equations.
y = -1 + 3/8(8)
y = -1 + 3
y = 2
2(8) - 5y = 6
16 - 5y = 6
-5y = -10
y = 2
(8,2)
Here's the general formula for bacteria growth/decay problems
Af = Ai (e^kt)
where:
Af = Final amount
Ai = Initial amount
k = growth rate constant
<span>t = time
But there's another formula for a doubling problem.
</span>kt = ln(2)
So, Colby (1)
k1A = ln(2) / t
k1A = ln(2) / 2 = 0.34657 per hour.
So, Jaquan (2)
k2A = ln(2) / t
<span>k2A = ln(2) /3 = 0.23105 per hour.
</span>
We need to use the rate of Colby and Jaquan in order to get the final amount in 1 day or 24 hours.
Af1 = 50(e^0.34657(24))
Af1 = 204,800
Af2 = 204,800 = Ai2(e^0.23105(24))
<span>Af2 = 800</span>