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3 years ago

SOLVE 7-9 I WILL GIVE BRAINLIST

Mathematics

1 answer:

Mashcka [7]3 years ago

7 0

Answer:

7. Approximately 402.7 inches or 2pi times 64

8. 31.83 To solve this you know 2pi r is an equation for the radius. 2πr=200 and r=200/2π=100/π= 31.83.

9. The one with pi in the equation because 3.14 is only a piece of pi but the symbol represents the whole number which goes on forever.

Step-by-step explanation:

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ASAP Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 f

Nitella [24]

Answer:

D. 6 feet.

Step-by-step explanation:

The third longest side of ABCD is 12 feet long and the third longest side of EFGH is 18 feet long.

As they are similar the corresponding sides are in the same ratio so

12/18 = x/9 where x is the 4th side of ABCD.

2/3 = x/9

3x = 18

x = 6 feet.

3 0

3 years ago

Please help! (Also show work)<br> Tutorials :D

oksano4ka [1.4K]

The five-number summary is:

Minimum: 9

First Quartile: 16.5

Median: 25.5

Third Quartile: 39

Maximum: 51

3. Range = 42

4. Interquartile range = 22.5

<h3>How to Find the Five-number Summary of a Data?</h3>

Given the data for the lengths as, 36, 15, 9, 22, 36, 14, 42, 45, 51, 29, 18, 20, to find the five-number summary of the data set, we would follow the steps below:

1. The numbers in ordered from the smallest to the largest would be:

9, 14, 15, 18, 20, 22, 29, 36, 36, 42, 45, 51

2. The five-number summary for the lengths in minutes would be:

Minimum value: this is the smallest lengths, which is 9
First Quartile (Q1): this is the middle of the first half of the data set of the lengths in minutes, which is 16.5.
Median: the median is the center of the data distribution which is 25.5.
Third Quartile: this is the middle of the second half of the data set of the lengths in minutes, which is 39.
Maximum: this is the largest length in minutes, which is, 51.

3. Range of the data = max - min = 51 - 9 = 42

4. The interquartile range for the data set = Q3 - Q1 = 39 - 16.5

Interquartile range for the data set = 22.5

Learn more about the five-number summary on:

brainly.com/question/24809873

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6 0

1 year ago

7) I am saving up for a video game. I currently have $28. If this is 30% of the

Snezhnost [94]

Answer:

93.3333333333 I think

7 0

3 years ago

Algebraic fractions<br> x² + 5x+4 /<br> x²+ 4x + 3

Tresset [83]

Answer:

$\frac{x+4}{x+3}$

Step-by-step explanation:

Given

$\frac{x^2+5x + 4}{x^2+4x+3}$ ← factor numerator and denominator

= $\frac{(x+1)(x+4)}{(x+1)(x+3)}$ ← cancel common factor (x + 1) on numerator/ denominator

= $\frac{x+4}{x+3}$

8 0

3 years ago

The school librarian, Mr. Marker, knows the library has 1,400 books but wants to reorganize how the books are displayed on the s

kipiarov [429]

Answer:

200 resource books

800 fiction books

400 nonfiction books

Step-by-step explanation:

Let's define x as the amount of resource books that are in the library. As he has four times as many fiction books as resource books, that means he has 4*x fiction books.

We also know he has half as many nonfiction books as fiction books, that is 1/2*4*x = 2*x nonfiction books.

We just need to find out the value of x.

We know there are 1,400 books in total and there are just 3 types of books. Therefore, if we sum all of them, we get the 1,400.

Written in math language, that is

x + 4x + 2x = 1,400

7x = 1,400

We divide by 7 on both sides and we get

7/7x = 1,400/7

x = 200

Now we replace the x with 200 to know how many books he has of each type:

Resource books = x = 200

Fiction books = 4*x = 4*200 = 800

Nonfiction books = 2*x = 2*200 = 400

Therefore, there are 200 resource books, 800 fiction books and 400 nonfiction books in the library.

The tape diagram is attached as an image.

8 0

3 years ago