I don’t know about y but x=35 they are diagonal from one another so they will be the same
If the base were 1, then the final value would never change...it would be a constant...
If the base is between zero and one, it is an exponential decay equation, so the final value would continually get smaller and smaller...
By graphing the given equation
<span>r = 4 - 3 sin θ
We find that </span><span>the graph is symmetric about the y-axis
The graph of the given equation is attached below
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Some information about the given equation:
the given equation is like the form of the </span>
Cardioid
A curve that is somewhat heart shaped. A cardioid can
be drawn by tracing the path of a point on
a circle as the circle
rolls around a fixed circle of the
same radius.
The equation is usually written in polar
coordinates.
Equations of Cardioid:
r = a ± a cos θ (horizontal)
or <span>r = a ± a sin θ (vertical)</span>
Answer:
8 hours
Step-by-step explanation:
If he writes 2 pages a hour and needs 16 pages, then you would have to divide 16 by 2 which is 8.
To double check that, you can multiply 8 by 2 which is 16.
You answer is 5 hours.
Complete Question
Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.
Answer:
a
The Fermi function for the energy KT is 
b
The temperature is 
Step-by-step explanation:
From the question we are told that
The energy considered is 
Generally the Fermi function is mathematically represented as
![F(E_o) = \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }](https://tex.z-dn.net/?f=F%28E_o%29%20%3D%20%20%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B%5BE_o%20-%20E_F%5D%7D%7BKT%7D%20%7D%20%2B%201%20%7D)
Here K is the Boltzmann constant with value 
is the Fermi energy
is the initial energy level which is mathematically represented as

So
![F(E_o) = \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}](https://tex.z-dn.net/?f=F%28E_o%29%20%3D%20%20%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B%5B%5BE_F%20%2B%20KT%5D%20-%20E_F%5D%7D%7BKT%7D%20%7D%20%2B%201%7D)
=> 
=> 
=> 
Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the Fermi function as
![F(E_k) = \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 } = 0.01](https://tex.z-dn.net/?f=F%28E_k%29%20%3D%20%20%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B%5BE_k%20-%20E_F%5D%7D%7BKT_k%7D%20%7D%20%2B%201%20%7D%20%20%3D%200.01)
Here
is that energy level that is 0.5 ev above the Fermi energy 
=> ![F(E_k) = \frac{1}{e^{\frac{[[0.50 eV + E_F] - E_F]}{KT_k} } + 1 } = 0.01](https://tex.z-dn.net/?f=F%28E_k%29%20%3D%20%20%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B%5B%5B0.50%20eV%20%2B%20E_F%5D%20-%20E_F%5D%7D%7BKT_k%7D%20%7D%20%2B%201%20%7D%20%20%3D%200.01)
=> ![\frac{1}{e^{\frac{0.50 eV ]}{KT_k} } + 1 } = 0.01](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Be%5E%7B%5Cfrac%7B0.50%20eV%20%5D%7D%7BKT_k%7D%20%7D%20%2B%201%20%7D%20%20%3D%200.01)
=> ![1 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} } + 0.01](https://tex.z-dn.net/?f=1%20%3D%200.01%20%2A%20e%5E%7B%5Cfrac%7B0.50%20eV%20%5D%7D%7BKT_k%7D%20%7D%20%2B%200.01)
=> ![0.99 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} }](https://tex.z-dn.net/?f=0.99%20%3D%200.01%20%2A%20e%5E%7B%5Cfrac%7B0.50%20eV%20%5D%7D%7BKT_k%7D%20%7D)
=> ![e^{\frac{0.50 eV ]}{KT_k} } = 99](https://tex.z-dn.net/?f=e%5E%7B%5Cfrac%7B0.50%20eV%20%5D%7D%7BKT_k%7D%20%7D%20%20%3D%2099)
Taking natural log of both sides
=> 
=> 
Note eV is electron volt and the equivalence in Joule is 
So

=> 