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2 years ago

1/2(c-8)= can someone please help me??

Mathematics

1 answer:

jolli1 [7]2 years ago

4 0

Answer:

that answer is 8 and half

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Subtract the polynomials.

Mama L [17]

Answer:

Step-by-step explanation:

Given

(4x² - 3x - 4) - (3x² + 4x - 8) ← distribute by - 1

= 4x² - 3x - 4 - 3x² - 4x + 8 ← collect like terms

= x² - 7x + 4 → B

8 0

2 years ago

Read 2 more answers

6×11÷2what do you think it could be

Valentin [98]

6x11÷2
6 x 11 is 66
66 ÷ 2 is 33
The answer is 33

7 0

2 years ago

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A 95% confidence interval is (70,110). what is the margin for error? A. 19 B.38 C.20 D.40

goldfiish [28.3K]

Answer:

C.20

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

In this question:

Lower bound: 70

Upper bounf: 110

Margin of error:

$M = \frac{110 - 70}{2} = \frac{40}{2} = 20$

Thus the correct answer is given by option C.

3 0

2 years ago

The baseball team has a double-header on Saturday. The probability that they will win both games is 18%. The probability that th

zhannawk [14.2K]

I got 30%
60% as a decimal is 0.6
18% as a decimal is 0.18
0.6 times 30% or 0.3 is 0.18

8 0

3 years ago

Read 2 more answers

I rlly rlly rlly need help! Complete the following proof. Given: Points R, S, T, Q on circle O Prove: m\overarc RS + m\overarc S

harina [27]

Answer:

$m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major\ arc RQ) = 360\ degree$

Step-by-step explanation:

As we can see in the figure that

The R, S, T ,and Q are the points on the circle O.

Also

The measurement of the circular arc is equivalent to the measurement of the angle at the center of the arc

So by this

$m(\widehat{RS})=m(\angle ROS)$

$m(\widehat{ST})=m(\angle SOT)$

$m(\widehat{TQ})=m(\angle TOQ)$

m(major arc RQ) = m(∠QOR)

So,

$m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major\ arc RQ) = m(\angle ROS)+m(\angle SOT)+m(\angle TOQ)+m(\angle QOR)$

And as we know that

All angles sum = 360°

Therefore

$m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major\ arc RQ) = 360\ degree$

8 0

3 years ago