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stellarik [79]
2 years ago
7

6n−8(n+4)= what? Please help me

Mathematics
2 answers:
jok3333 [9.3K]2 years ago
7 0

Answer:

-2n -32

Step-by-step explanation:

Acc. to BODMAS

we multiply first

⇒-6n - -8 x [(+4) (n)]

⇒ 6n  - 8n x -32

velikii [3]2 years ago
4 0

\huge\text{Hey there!}


\huge\textbf{Equation:}

\mathsf{6n - 8(n + 4)}


\huge\textbf{Solve: }

\mathsf{6n - 8(n + 4)}


\huge\textbf{Distribute \boxed{\bf -8} within the parenthesis:}

\mathsf{= 6n - 8(n) - 8(4)}

\mathsf{= 6n - 8n - 32}


\huge\textbf{Combine the like terms: }

\mathsf{= (6n - 8n) - (32)}

\mathsf{= 6n - 8n - 32}

\mathsf{= -2n  - 32}


\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\frak{{ -2n  - 32}}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}}

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Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
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\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0
3 years ago
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