9514 1404 393
Answer:
1250 square feet
Step-by-step explanation:
If x is the length of the side perpendicular to the creek, then the third side is (100 -2x) = 2(50 -x). The area is the product of length and width:
A = x(2)(50-x)
We observe that this is a quadratic function with zeros at x=0 and x=50. The vertex (maximum) of a quadratic function is on the line of symmetry, halfway between the zeros. The value of x there is (0 +50)/2 = 25.
Then the maximum area is ...
A = (25)(2)(50 -25) = 1250 . . . . square feet
_____
<em>Additional comment</em>
Note that half the length of the fence is used in one direction (parallel to the creek), and half is used in the other direction (perpendicular to the creek). This 50/50 split is the generic solution to all sorts of rectangular corral problems, with or without a creek, with or without internal partitions.
Half the fence is perpendicular to the other half. (If the costs are different in different directions, then the cost is what is split 50/50.)
Heya Mate
We need to find the value of variable over here
A ) 6 x = 12
→ x = 2
[ since , Transposing constant from Left to right , Opression is changed from Multiply to Division ]
B ) 3n = 9
→ n = 3
[ Opression is changed from Multiply to Division ]
C ) 11t = 23
→ t = 11.5
D ) 36 = 9k
→ 9k = 36
→ k = 4
Hope this helps you
Hello!
To find the side length you use the equation
![a = \sqrt{2} \frac{d}{2}](https://tex.z-dn.net/?f=a%20%3D%20%20%5Csqrt%7B2%7D%20%20%5Cfrac%7Bd%7D%7B2%7D%20)
a is side length
d is diagonal
Put in the number we know
![a = \sqrt{2} * \frac{27}{2}](https://tex.z-dn.net/?f=a%20%3D%20%20%5Csqrt%7B2%7D%20%2A%20%20%5Cfrac%7B27%7D%7B2%7D%20)
Divide
![a = \sqrt{2} * 13.5](https://tex.z-dn.net/?f=a%20%3D%20%20%5Csqrt%7B2%7D%20%2A%2013.5)
Multiply
a = 19.091
The answer is 19.09
Hope this helps!
Step-by-step explanation:
3800 is the general amount, but before he can touch it, 800 and 200 are taken away from it for the described purposes.
so, what is left is
3800 - 800 - 200 = 2800
this is then the real amount he can do something with.
Answer:
The perimeter of the trapezoid is ![38.25\ units](https://tex.z-dn.net/?f=38.25%5C%20units)
Step-by-step explanation:
we know that
The perimeter of the trapezoid is the sum of its four side lengths
so
In this problem
![P=QR+RS+ST+QT](https://tex.z-dn.net/?f=P%3DQR%2BRS%2BST%2BQT)
the formula to calculate the distance between two points is equal to
we have
![Q(8, 8), R(14, 16), S(20, 16),T(22, 8)](https://tex.z-dn.net/?f=Q%288%2C%208%29%2C%20R%2814%2C%2016%29%2C%20S%2820%2C%2016%29%2CT%2822%2C%208%29)
step 1
Find the distance QR
![Q(8, 8), R(14, 16)](https://tex.z-dn.net/?f=Q%288%2C%208%29%2C%20R%2814%2C%2016%29)
substitute the values in the formula
step 2
Find the distance RS
![R(14, 16), S(20, 16)](https://tex.z-dn.net/?f=R%2814%2C%2016%29%2C%20S%2820%2C%2016%29)
substitute the values in the formula
step 3
Find the distance ST
![S(20, 16),T(22, 8)](https://tex.z-dn.net/?f=S%2820%2C%2016%29%2CT%2822%2C%208%29)
substitute the values in the formula
step 4
Find the distance QT
![Q(8, 8),T(22, 8)](https://tex.z-dn.net/?f=Q%288%2C%208%29%2CT%2822%2C%208%29)
substitute the values in the formula
step 5
Find the perimeter
![P=10+6+8.25+14=38.25\ units](https://tex.z-dn.net/?f=P%3D10%2B6%2B8.25%2B14%3D38.25%5C%20units)