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Sphinxa [80]
3 years ago
13

The Ohio State Buckeyes gained 8 yards, lost 4 yards, then gained 20 yards. How many total yards were gained or lost during the

3 plays?
Mathematics
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

Gained 24 yards

Step-by-step explanation:

8 - 4 + 20 =

4 + 20 = 24 yards.

Your welcome!

Kayden Kohl

8th Grade Student

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How is x = 5 mathematically different from x > 5?​
Ivahew [28]

Answer:

in x>5 x is larger than 5

Step-by-step explanation:

x=5 means x is equal to 5

x>5 means x is greater than 5

7 0
3 years ago
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A^2+b^2=1305, a*b=648, a-b=?
luda_lava [24]

a - b is 9

Step-by-step explanation:

  • Step 1: Given a² + b² = 1305, a × b = 648. Find a - b using the identity for (a - b)²

⇒ (a - b)² = a² + b² - 2ab

⇒ (a - b)² = 1305 - 2 × 648 = 1305 - 1296 = 9

⇒ (a - b) = 9

7 0
3 years ago
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- What is the complete factorization of 4x2 – 24xy + 36y2 ?​
Rzqust [24]

<u>Answer: </u>

The complete factorization of 4 x^{2}-24 x y+36 y^{2} are 4(x-3y)(x+3y)

<u>Solution:</u>

Given Data:

4 x^{2}-24 x y+36 y^{2}

Take common value in all the three term.so we take 4 as common term in the above expression

4 x^{2}-24 x y+36 y^{2}=4\left(x^{2}-6 x y+9 y^{2}\right)

Now factorize the expression \left(x^{2}-6 x y+9 y^{2}\right)

Find the two numbers, whose product should be 9 and sum should be -6.

-3,-3 are the numbers which satisfy the above condition.

When we add -3-3=Sum is 6

Product of -3 \times -3= 9  

-3 , -3 satisfies the condition.

So the expression will become as x^{2}-6 x y+9 y^{2} = x^{2}-3 x y-3 x y+9 y^{2}

Take the common term

x(x-3y)+3y(x-3y)  

(x-3y)(x+3y)  

hence the complete factorization of 4 x^{2}-24 x y+36 y^{2} are 4(x-3y)(x+3y)

5 0
3 years ago
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mafiozo [28]
Hi I’m just testing this out, sorry
7 0
4 years ago
PLEASE HURRY write the equation of the inverse function y=1/2cos^-1(pix)-3
GaryK [48]

Answer:

f^{-1}(x) = \frac{cos(2x+6)}{\pi }

Step-by-step explanation:

y = \frac{1}{2} cos^{-1} (\pi x)-3

Firstly, we've to interchange the variables.

x = \frac{1}{2} cos^{-1}(\pi y)-3

Solving for y

x = \frac{cos^{-1} \pi y}{2} -3

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Dividing both sides by y

y = \frac{cos(2x+6)}{\pi }

Replace y by f^{-1}(x)

=> f^{-1}(x) = \frac{cos(2x+6)}{\pi }

4 0
3 years ago
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