1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VLD [36.1K]
1 year ago
15

Graph 4x + y = 6x - 1 Show your work and explain the method used to determine the graph.

Mathematics
1 answer:
Maru [420]1 year ago
3 0

See attachment for the graph of y = 2x - 1

<h3>How to graph the function?</h3>

The equation of the function is given as:

4x + y = 6x - 1

Subtract 4x from both sides of the equation

y = 2x - 1

This means that the equivalent equation of 4x + y = 6x - 1 is y = 2x - 1

So, we plot the graph of y = 2x - 1 to represent the equation 4x + y = 6x - 1

See attachment for the graph of y = 2x - 1

Read more about linear equations at

brainly.com/question/14323743

#SPJ1

You might be interested in
Your housing and fixed expenses are $685.70/month. If they are 33% of your realized income, how much is your realized income per
galben [10]
$685.70÷33%=$2,077.88
A
4 0
3 years ago
Read 2 more answers
Which graph represents a function?
Temka [501]

Answer:

The last one

Step-by-step explanation:

x can only have one value whereas y can be constants like in last graph

6 0
3 years ago
Read 2 more answers
How much is 50% of 10 liters of milk
juin [17]

Answer:

5 liters

Step-by-step explanation:

10 x 0.5 = 5

4 0
3 years ago
Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
3 years ago
It snowed from 9:43 PM to 11:37 PM. How long was it snowing?
dolphi86 [110]

Answer:

1 hour and 54 minutes and ignore this stuff sjsjsbdbsj

4 0
3 years ago
Read 2 more answers
Other questions:
  • If a = 2.3 units, b = 4 units, c = 6 units, and d = 8 units, what is the volume of the two prisms?
    12·1 answer
  • There are 9 members on a board of directors. If they must select a chairperson, a secretary, and a treasure, how many different
    9·1 answer
  • Find 7 1/2 divided by 2 1/2. Simplify and write as mixed number
    8·2 answers
  • The integer -3 would BEST represent which of these events? A) I only B) III only C) I and III only D) II and III only im g
    14·2 answers
  • Which graph best represents y=2^x + 1
    9·1 answer
  • Multiply: (5x − 2)(4x2 − 3x − 2)?
    14·1 answer
  • Need help will give brainiest
    8·1 answer
  • The illustration below shows the graph of y as a function
    12·1 answer
  • ASP PLZ
    13·2 answers
  • A teacher wrote this expression on the board (-6)(2)+(-8+4)
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!