The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
6.6 cm and 14.6 cm
Step-by-step explanation:
(a)
the length of arc AB is calculated as
AB = circumference of circle × fraction of circle
= 2πr × 
= 2π × 4 × 
= 8π × 
= 
≈ 6.6 cm ( to the nearest tenth )
(b)
the perimeter (P) of sector AOB is
P = r + r + AB = 4 + 4 + 6.6 = 14.6 cm
Answer:
3.44 x 10^6
Step-by-step explanation:
41 x 8.4 = 344.4
344.4 x 10^4 = 3.44 x 10^4+2
x1= -5 x2=0.5 y= -5
the answer is b as the minuses can be interchanged for the x intercepts
Step-by-step explanation:
As you can see as explained in the pictures
Answer:
46
Step-by-step explanation:
With those problems if you are not given a picture is good we draw one.
Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW then
m < XVY = m < YVW
2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms
2x-x = 15-7, combine like terms
x = 8
From the picture and the given we see that
m < XVW = m < XVY + m < YVW
m < XVW = 2x+7 + x+15 , combine like terms
m < XVW = 3x + 22, substitute x for 8
m < XVW = 3*8 + 22
m < XVW = 46
Check our work:
m < XVY = 2x+7 = 2*8 +7 = 16 +7 = 23
m < YVW = x+15 = 8 +15 = 23
m < XVW = m < XVY + m < YVW = 23+23 =46