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3 years ago

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Mathematics

1 answer:

tankabanditka [31]3 years ago

3 0

Answer:

skin tone chicken bone leave me alone

but jk for real the answer is b or c but I would go for B

good luck and I hope you get it right let me know if its wrong

Step-by-step explanation:

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9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat

Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 2000, p = 1-0.995 = 0.005$

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

$P(X < 5) + P(X \geq 5) = 1$

We want $P(X \geq 5)$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044$

$P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445$

$P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235$

$P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480$

$P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765$

$P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290$

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710$

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0

3 years ago

1 2/3 divided by (-2 3/4)

MAVERICK [17]

Answer:

I think its -20/33- Im not that confident but i worked it out :)

6 0

2 years ago

Solve for brainliest please

velikii [3]

Answer: The value of d 62 + 5

4 0

3 years ago

Read 2 more answers

The difference of a number and 9 <br><br> •write as a algebraic expression

otez555 [7]

Answer:

x - 9

Step-by-step explanation:

5 0

3 years ago

Hey there! Can anyone help me out with this? I need help with both of these. Will give brainliest! :D

coldgirl [10]

$area = length \times width$

____________________________________________

c .

$area = \frac{3}{8} \times \frac{4}{5} \\$

$area = \frac{4 \times 3}{4 \times 2 \times 5} \\$

$area = \frac{3}{2 \times 5} \\$

$area = \frac{3}{10} \: \: {cm}^{2} \\$

_____________________________________________

$area = \frac{1}{4} \times \frac{3}{7} \\$

$area = \frac{3}{28} \: \: {m}^{2} \\$

4 0

3 years ago