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Allushta [10]
2 years ago
15

I have one try left on this problem

Mathematics
1 answer:
Rom4ik [11]2 years ago
7 0

Answer:

632

Step-by-step explanation:

So we can define decreasing x% in two ways: we can define 20% off as 80% of the original value, or we can define subtracting 20% from the original value, and both representations are useful.

In this case it's more useful to define 20% as subtracting 20%, from the original value. The reason for this, is because since we're subtracting 20% of the original value, we then know that 126.40 is 20% the original value.

So to find x% of some value, you generally use the following equation: A*\frac{x}{100} where A=original amount, and x is the percent. This equation is simply converting the x% to a decimal value. Since 126.40 is 20%, we can derive the following equation.

0.20A = 126.40

We can solve for A, by dividing by 0.20

A=632\\

It's also important to note, you didn't really have to set up this entire equation, since you know that the 126.40 is 20%, you simply could've multiplied by 5, since 20% is really just 1/5 of the entire value, so get the entire value, or original value you multiply by 5

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Use completing the square to determine which of the following gives the solutions to 3x2 - 24x + 40 = 28.
jeka94

Answer:

x=4+2\sqrt{3}

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Step-by-step explanation:

<u>Completing the square</u>

when  ax^2+bx+c=0

Given equation:

3x^2-24x+40=28

Subtract 40 from both sides:

\implies 3x^2-24x=-12

Divide both sides by 3:

\implies x^2-8x=-4

Add the square of half the coefficient of x to both sides:

(\frac{b}{2})^2=(\frac{-8}{2})^2=16

\implies x^2-8x+16=-4+16

Factor the left side and simplify the right side:

\implies (x-4)^2=12

Square root both sides:

\implies x-4=\pm\sqrt{12}

Add 4 to both sides and simplify the radical:

\implies x=4\pm\sqrt{4 \cdot 3}

\implies x=4\pm\sqrt{4}\sqrt{3}

\implies x=4\pm2\sqrt{3}

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2 years ago
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Angelina_Jolie [31]

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

When a function has a zero, simply put, that point is where the graph goes through the x-axis.  At this point, the y value is 0.

If a function has a 0 of 1/2, that translates to x = 1/2 and also (1/2, 0).  That means that y = 0 when x = 1/2.

If x = 1/2 and is a zero, then x - 1/2 = 0 and 2x - 1 = 0 (notice that y = 0 here and solving for x would get you right back to x = 1/2).

The simplest function with a zero of 1/2 is

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You know it is true that the zero is 1/2 for two reasons.  First one is to set the right side equal to 0 and solve for x.

The second one is to graph the line y = 2x - 1 and see that it goes through the x axis at 1/2 where y = 0.

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