Question

A globe company currently manufactures a globe that is 16 inches in diameter. if the dimensions of the globe were reduced by half, what would its volume be? use 3.14 for π and round your answer to the nearest tenth.

Answer 1

The volume of the new globe will be $803.84 inch^3$

Solution:

Diameter = 16inch

Radius = $\frac{Diameter}{2}$ = $\frac{16}{2}$ = 8inches

New Radius = $\frac{radius}{2}$ = $\frac{8}{2}$ = 4 inches

We know that

Volume of a sphere = $\frac{4\pi r^3}{3}$

V = $\frac{4 \times 3.14\times4^3}{3}$ = $803.84 inch^3$

What is Volume?

• Volume is a measurement of three-dimensional space that is occupied. Numerous imperial units or SI-derived units, such as the cubic meter and liter, are frequently used to quantify it numerically (such as the gallon, cubic inch).
• In contrast to how much space the container actually occupies, the volume of a container is typically thought of as its capacity, or the amount of fluid it could hold.
• Arithmetic formulas can be used to quickly calculate the volume of several straightforward three-dimensional shapes. If a formula for the shape's boundary is known, it is possible to use integral calculus to determine the volumes of more complex shapes.
• No object in the dimensions of zero, one, or two has volume; in the dimensions of four and above, the hypervolume is a concept similar to the standard volume.

To learn more about volume with the given link

brainly.com/question/1578538

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