Answer:
B. $12,500
Explanation:
Accumulated depreciation is the cumulative depreciation of an asset up to a single point or current point in its life.
Each period, the depreciation expense recorded in that period is added to the beginning accumulated depreciation balance. Therefore when there's an entry of depreciation of an equipment, the current value is added to the previous total of the old entry. Therefore the balance of the the depreciation after current entry is the beginning balance of the depreciation plus the balance entered into the record.
In this case, the beginning balance was $10,000 and the entry was $2,500
Hence, balance of accumulated depreciation account after entry is 10000 + 2500 = $12,500
Answer:
Problem statement
Explanation:
Problem statement - it is referred to as the statement that given the clear and crystal information about the current situations. it is considered a good source of analyzing the real situations about the ongoing project.
This statement describes the current situations between the current and desired aim of the projects. it expressed the problem in two or three statements.
Answer:
C
Explanation:
Reduction of cost basis per share.
When you take a look at some of the rules that IRS has, you see that stock dividends do not get taxsd at the time of receipt. They don't get taxed because, the shareholder does not receive anything from the company, only but a hope on any increased future share price increment or appreciation.
Answer:
Explanation:
a.Present value of inflows=cash inflow*Present value of discounting factor(rate%,time period)
=150,000/1.12+210,000/1.12^2+360,000/1.12^3
=557580.18
NPV=Present value of inflows-Present value of outflows
=557580.18-460,000
=$97580.18(Approx)=Value of factory
b.Hence since net present value is positive;factory is a good investment
(Yes)
Answer: 4 containers
Explanation:
The formula used to get the number of containers that are needed will be:
N = DT(1+X)/C
where,
N = total containers
D = planned usage rate used by the work center = 111 parts per hour
T = average waiting time = 100 minutes = 100/60 hours = 1.67 hours
X = inefficiency factor = 0.21
C = capacity of standard container = 5 dozens = 5 × 12 = 60 parts
N = DT(1+X)/C
N = (111 × 1.67)(1 + 0.21)/60
N = (185.37 × 1.21)/60
N = 224.2977/60
N = 3.738
N = 4 approximately
4 containers will be needed
