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Anna [14]
2 years ago
11

A circle circumference is 600 M. what is the good approximation of the circle area​

Mathematics
1 answer:
wlad13 [49]2 years ago
4 0

Answer:

The area of the circle is 28662 M².

Step-by-step explanation:

Given:

Circumference of circle = 600 M.

Now, to find the area of the circle.

So, <em>to get the area we need to find the radius.</em>

By putting the formula of circumference we get the radius:

Let the radius be r.

Circumference = 2πr

600 = 2\times 3.14\times r (taking the value of π = 3.14.)

600=6.28r

Dividing both sides by 6.28 we get:

95.54=r

Now, <em>for getting the area we put the formula:</em>

Area = πr²

Area = 3.14\times 95.54^{2}

Area = 3.14\times 9127.89

Area = 28661.57

So, <u><em>approximately the area of  the circle = 28662 M²</em></u>.

Therefore, the area of the circle is 28662 M².

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The answer to the question

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3 years ago
If u = 2i - j; v= -5i + 4j and w = j find 4u (v -w).
Sedaia [141]

Answer:

-40

Explanation:

Given

u = 2i - j; v= -5i + 4j and w = j

Required

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4u = 4(2i) = 8i

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v - w = -5i + 3j

Substitute

4u(v-w)

= 8i(-5i+3j)

= -40(i*i) [since i*i = 1]

= -40

Hence the required solution is -40

5 0
1 year ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

Now evaluating the integral using calculator,

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




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3 years ago
The graph below is the solution for which sets of inequalities?
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Answer:

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Step-by-step explanation:

i did the test and got it right

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A planet's radius is approximately 1,534 mi. About two-thirds of the planet's surface is covered by water.
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Step-by-step explanation:

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