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maks197457 [2]
1 year ago
10

A scientist used a microscope to count the number of bacterial cells in a petri dish every hour. The graph shows the data collec

ted. Which function MOST accurately represents this data, where n is the number of bacteria and t is the time elapsed, in hours?

Mathematics
1 answer:
Alex777 [14]1 year ago
8 0

The required relationship shown by the graph is the exponential relationship n =2^t . Option a is correct,

Given that,

A graph has been shown, showing the data,  what is the relationship between the number of bacteria with time is to be determined.

<h3>What is a graph?</h3>

The graph is a demonstration of curves that gives the relationship between the x and y-axis.

Since the recorded value from the graph is
At, t = 1 ; n = 2
At t = 2 ; n = 4
At t = 3 ; n = 8
At t = 4 ; n = 16
At t = 5 : n = 32
Here the above data show the exponential relation between n and t with the base value 2 i.e. n =2^t

Thus, the required relationship shown by the graph is the exponential relationship of n =2^t . Option a is correct,


Learn more about graphs here:

brainly.com/question/16608196

#SPJ1

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What are the range values of the function f (x ) = 3x + 4 for the domain values {-5, -1, 0, 2, 7}?
Airida [17]

Answer:

Range values are:

{-11, 1, 4, 10, 25}

Step-by-step explanation:

Domain values are the possible x values that can be entered into the function, or the inputs.  Range values are the y values, or the outputs. By inserting every value in the set into the function, we get the outputs (y values)

-15 + 4 = -11

-3+4 = 1

0 + 4 = 4

6 + 4 = 10

21 + 4 = 25

Remember to put them in order.

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Answer:

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Step-by-step explanation:

4 0
3 years ago
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solniwko [45]

The answer will be option 2. 10^4.

8 0
2 years ago
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According to the data, the mean quantitative score on a standardized test for female college-bound high school seniors was 500.
Sveta_85 [38]

Answer:

6.68% of the female college-bound high school seniors had scores above 575.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 50

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(scores above 575)

P(x > 575)

P( x > 575) = P( z > \displaystyle\frac{575 - 500}{50}) = P(z > 1.5)

= 1 - P(z \leq 1.5)

Calculation the value from standard normal z table, we have,  

P(x > 575) = 1 - 0.9332= 0.0668 = 6.68\%

6.68% of the female college-bound high school seniors had scores above 575.

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The slope of a liner model represents the starting value.
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