The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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6Myd = 1
y= 1/6Md is the answer
Answer:
The slope-intercept form of the equation of the line is:
y = 2/3x + 2
Step-by-step explanation:
The slope-intercept form of the line equation
y = mx+b
where
Given the points
(x₁, y₁) = (0, 2)
(x₂, y₂) = (3, 4)
Using the formula
Slope = m = [y₂ - y₁] / [x₂ - x₁]
= [4 - 2] / [3 - 0]
= 2 / 3
Thus, the slope of the line = m = 2/3
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
From the graph, it is clear
at x = 0, y = 2
Thus, the y-intercept b = 2
now substituting m = 2/3 and b = 2 in the slope-intercept form
y = mx+b
y = 2/3x + 2
Therefore, the slope-intercept form of the equation of the line is:
y = 2/3x + 2
Answer:
Explanation:
-8 = (x + 11)/2
-8 • 2 = x + 11
-16 = x + 11
-16 - 11 = x
-27 = x
Or x = -27
Check:
-8 = (-27 + 11)/2
-8 = -16/2
-8 = -8
Therefore, x = -27
Answer:
Total Surface Area of the given regular pyramid = 153 units²
Step-by-step explanation:
Base length of the regular pyramid, l = 9 units
Base width of the regular pyramid, w = 9 units
Height of the regular pyramid, h = 7 units
Perimeter of base = 3 × 9
= 27 units
Hence, Total Surface Area of the given regular pyramid = 153 units²