5 is B. 6 is C. 7 is D. And 8 is A :)
Answer:
pretty sure its 1/4 x 1/4 x 1/4 x 1/4
Step-by-step explanation:
we know its diameter is 12, thus its radius must be half that, or 6.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=6 \end{cases}\implies A=\pi 6^2\implies A=36\pi \implies A\approx 113.097](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D6%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%206%5E2%5Cimplies%20A%3D36%5Cpi%20%5Cimplies%20A%5Capprox%20113.097)
Unsure of what you mean by "6-23." There's no subtraction in this problem.
If you meant "6/23," then "doubling" that results in 12/23 cups. Still, that does not look right. Go back and ensure that you have copied down the original problem exactly.
