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Lerok [7]
3 years ago
12

Figure A is a scale image of figure B. Figure A maps to figure B with a scale factor of 2 1/2. What is the value of x? PLEASE AN

SWER ASAP!!

Mathematics
1 answer:
tigry1 [53]3 years ago
3 0

Answer:

x = 2

Step-by-step explanation:

Figure B = 2½ the size of figure A

One side of figure B is given as 5, therefore, 5 = 2½ of x in figure A.

Thus, 5 = 2\frac{1}{2}*x

Solve for x

5 = \frac{5}{2}*x

5*2 = \frac{5x}{2}*2

10 = 5x

\frac{10}{5} = \frac{5x}{5}

2 = x

x = 2

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Use this equation and you will find:

y = -2 - 4

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Answer: (2, -6)

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6 0
3 years ago
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insens350 [35]
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IGJ and IGH

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7 0
3 years ago
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Blizzard [7]
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6 0
3 years ago
What is the range of the function f(x) = 3x2 + 6x – 8?
timama [110]

Answer:

Range is {y | y ≥ –11}


Step-by-step explanation:

This is quadratic equation.

<em>A quadratic equation's range can be found if we find the vertex.</em>

For quadratic equations that have a positive number in front of  x^{2} , it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>


The formula for vertex of a parabola is:

Vertex =  (-\frac{b}{2a}, f(-\frac{b}{2a})

Where,

  • a is the coefficient of x^{2}
  • b is the coefficient of x

From our equation given, a=3  and  b=6

Now, x coordinate of vertex is  x=-\frac{b}{2a}\\x=-\frac{6}{(2)(3)}\\x=-\frac{6}{6}\\x=-1

y coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the x value [ x=-1 ] into the equation. So we have:

3(-1)^{2}+6(-1)-8\\=-11


Hence, the range would be all numbers greater than or equal to -11  

Third answer choice is the right one.


6 0
3 years ago
Read 2 more answers
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