The values of the function when x = 1 are y = 1 and y = 1
<h3>How to choose one value that is in the domain of both y(x) = x^2 and y^2 = x?</h3>
The functions are given as:
y(x) = x^2
y^2 = x
Also, the graphs of the functions are given.
From the given graph, we have:
- The domain of y(x) = x^2 is the set of all real numbers
- The domain of y^2 = x is the set of all real numbers greater than or equal to 0
The common numbers in both domain are represented by x >= 0
An example of such number is
x = 1
So, we have:
y(1) = 1^2 ⇒ y(1) = 1
y^2 = 1 ⇒ y = 1
Hence, the values of the function when x = 1 are y = 1 and y = 1
Read more about domain and range at:
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Answer:
the answer is 20 thousendth
Answer:
Part A - D:8
Part B - C:140°
<h3>Solving/Reasoning:</h3>
Part A: Vertical angles are always congruent.
Part B: If angles are supplementary, they need to equal 180 when added together. Since we know angle A is 40, we can subtract it from 180 and figure out what is left over that should be angle B.
40+B=180
B=180-40
B=140
Answer: 240
Step-by-step explanation: V=whl=6·5·8=240
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