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4vir4ik [10]
3 years ago
12

Estimate the weight of 6 apples.

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0
The answer:  1533 g {"grams"} ;  or even "1530 g" or "1500 g" ; would be an acceptable estimate.
_______________________________________________________
<u><em>Note</em></u>:  We are asked to:  "Estimate the weight of 6 (six) apples."

Given: (from the table—within the image attached):  
_______________________________________________________
"2 apples weigh "511 g" ; 


"then "6 apples" would weigh about 3 times that weight;  since: 

  "2 apples;  multiplied by "3" , is "6 apples" .

so:  "511 g * 3 ≈  500 g * 3 = 1500 g ". 

or:  
"511 g * 3 ≈ 510 g * 3  = (500 g * 3)  + (10 g * 3) = (1500 + 30) g = 1530 g. 

or:   

"511 g * 3 ≈ 511 g * 3  = (500 g * 3)  + (11 g * 3) = (1500 + 33) g = 1533 g.
______________________________________________________
Note:  The table shows that the given numbers of apples, along with their respective weights, are not [evenly and equally] proportional —reflecting the fact that there is variation among weight in apples across the board.
______________________________________________________
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Answer:

The slopes are

m1=\dfrac{2}{5}, m2=-\dfrac{5}{2}

Therefore, the equations are equations of <u>  Perpendicular Lines .</u>

Step-by-step explanation:

Given:

y=\dfrac{2}{5}\times x + 1    ......................Equation ( 1 )

5x+2y=-4\\\\\therefore y = \dfrac{-5}{2}\times x-2   ..............Equation ( 2 )

To Find:

Slope of equation 1 = ?

Slope of equation 2 = ?

Solution:

On comparing with slope point form

y=mx+c

Where,

m = Slope

c = y-intercept

We get

Step 1.

Slope of equation 1 = m1 = \dfrac{2}{5}

Step 2.

Slope of equation 1 = m2 = -\dfrac{5}{2}

Step 3.

Product of Slopes = m1 × m2 = \dfrac{2}{5}\times -\dfrac{5}{2}=-1

Product of Slopes = m1 × m2 = -1

Which is the condition for Perpendicular Lines

The slopes are

m1=\dfrac{2}{5},m2=-\dfrac{5}{2}

Therefore, the equations are equations of <u>  Perpendicular Lines . </u>

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