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Lelechka [254]
3 years ago
15

Find the simplified product:

xFormula1" title="\sqrt{2x^{3} }-\sqrt{18x^{5} }" alt="\sqrt{2x^{3} }-\sqrt{18x^{5} }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
mash [69]3 years ago
7 0

Correct Question: Find the simplified product: \sqrt{2x^3}*\sqrt{18x^5}

Answer:

6x^4

Step-by-step explanation:

Based on the rules of radicals, since \sqrt{2x^3} and \sqrt{18x^5} has the same index (square root), therefore:

\sqrt{2x^3}*\sqrt{18x^5} = \sqrt{2x^3 * 18x^5}

To simplify this, multiply their bases together, and add their exponents.

= \sqrt{2*18x^{3+5}

= \sqrt{36x^{8}

Simplify further

= \sqrt{36}*\sqrt{x^8}

= \sqrt{6*6}*\sqrt{x^4*x^4}

= 6x^4

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6 0
3 years ago
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Bad White [126]

believe what you're asking is to turn the trinomial into two binomials

So you first have to get 3x²; the only way to get this is

(3x    )(x     )     when multiplying that, you would get 3x²

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5 0
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