2 years ago

Solve for problem 26 and solve for x please help

Mathematics

1 answer:

natulia [17]2 years ago

5 0

Answer:

$x= -1\frac{9}{23}$

Step-by-step explanation:

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Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

$n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )$

where $n\left ( N\cup E\right )=$ Students either nose or ear Pierced

$n\left ( N\cap E\right )=$ no of students having both nose and ear pierced

$40=7+36-n\left ( N\cap E\right )$

$n\left ( N\cap E\right )=43-40=3$

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4 years ago

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3 years ago

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kevin and randy muise have a jar containing 84 coins all of which are either quarters or nickels. the total value of the coins i

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Let the number of nickels be n, then the number of quarters is 84-n.
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Step-by-step explanation:

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