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gizmo_the_mogwai [7]
2 years ago
15

For s=5 and t=8, 3st²-s²: 3st²-s² =

Mathematics
1 answer:
melomori [17]2 years ago
8 0

Step-by-step explanation:

Given,

s=5

t=8

solution,

= 3st² - s²

= 3*5*8² - 5²

= 3*5*64 - 25

= 960 - 25

= 935

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Paladinen [302]

Answer:

a)  We get \mathbf{A+B=x^2-2x+1}

So, Is the result of A+B is a polynomial:Yes

b) We get \mathbf{A-B=6x^3-7x^2+2x-1}

So, Is the result of A-B is a polynomial:Yes

c)  We get \mathbf{A.B=9x^6+21x^5-18x^4+9x^3-3x^2}

So, Is the result of A.B is a polynomial:Yes

Step-by-step explanation:

We are giving the polynomial equations:

A= 3x^2(x-1)\\B=-3x^3+4x^2-2x+1

We need to find

a) A+B

A+B=3x^2(x-1)+(-3x^3+4x^2-2x+1)\\A+B=3x^3-3x^2-3x^3+4x^2-2x+1\\A+B=3x^3-3x^3-3x^2+4x^2-2x+1\\A+B=x^2-2x+1\\

So, we get \mathbf{A+B=x^2-2x+1}

So, Is the result of A+B is a polynomial:Yes

b) A-B

A-B=3x^2(x-1)-(-3x^3+4x^2-2x+1)\\A-B=3x^3-3x^2+3x^3-4x^2+2x-1\\A-B=3x^3+3x^3-3x^2-4x^2+2x-1\\A-B=6x^3-7x^2+2x-1\\

So, we get \mathbf{A-B=6x^3-7x^2+2x-1}

So, Is the result of A-B is a polynomial:Yes

c) A . B

A.B=3x^3(-3x^3+4x^2-2x+1)-3x^2(-3x^3+4x^2-2x+1)\\A.B=9x^6+12x^5-6x^4+3x^3+9x^5-12x^4+6x^3-3x^2\\A.B=9x^6+12x^5+9x^5-6x^4-12x^4+3x^3+6x^3-3x^2\\A.B=9x^6+21x^5-18x^4+9x^3-3x^2

So, we get \mathbf{A.B=9x^6+21x^5-18x^4+9x^3-3x^2}

So, Is the result of A.B is a polynomial:Yes

7 0
3 years ago
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Julli [10]
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2 years ago
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guapka [62]

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Step-by-step explanation:

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