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user100 [1]
3 years ago
5

kevin built a deck in his backyard. The length of the deck was 5x+1 units and the width of the deck was 4x-1 units. Write and si

mplify an expression to repersent the perimeter of kevins deck.
Mathematics
1 answer:
amm18123 years ago
7 0

Answer:

Perimeter =

2(length + width)  \\ 2(5x + 1 + 4x - 1) \\ 2(5x + 4x + 1 - 1) \\ 2(9x ) \\ 9 \times 2 \\  = 18

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The perimeter of a rectangle swimming pool is a 114 ft. The width is 7ft more than the lenth. Find lenght and width
Margaret [11]

Answer:

Length- 14 Width- 100

Step-by-step explanation:

First: 7x2=14

Then: 114-14=100

Hope this helps

-Mercury

7 0
3 years ago
Read 2 more answers
Please explain your answer
Ymorist [56]

Answer:

51

Step-by-step explanation:

11+(-7)^2-9 - original

11+49-9 - square the -7, since its in brackets the negative applies too and a negative x a negative = positive, so it ends up as 7x7+49

60-9 - add both positives 11+49=60

51 - subtract 9 from 60, 60-9=51

7 0
3 years ago
Write two equelivant ratios 11 and 4​
timofeeve [1]

Answer:

The answer is 8 : 22, 12:33 as they are two equelivant ratios 11 and 4

4 0
3 years ago
Gemma recently rode her bicycle to visit her friend who lives 6 miles away. On her way there, her average speed was 16 miles per
DochEvi [55]

first speed --- x mph

return speed -- x+16 mph

6/x + 6/(x+16) = 1

times each term by x(x+16)

6(x+16) + 6x = x(x+16)

x^2 + 4x - 96 = 0

(x-8)(x+12) = 0

x = 8 or x is a negative

her first speed was 8 mph

her return speed was 24 mph

check:

6/8 + 6/24 = 1 , that's good!

8 0
3 years ago
You place the spring vertically with one end on the floor. You then drop a book of mass 1.50 kg onto it from a height of 0.900 m
Alex777 [14]

Answer:

The value of the maximum distance the spring will be compressed  

x = 0.143 m= 14.3 cm

Step-by-step explanation:

Given data

Mass m = 1.5 kg

h = 0.9 m

k = 1500\frac{N}{m}

Since the book is released from a height h = 0.9 m above the top of the spring. so the total distance

y = h + x

Now in that case for the spring

mg y= \frac{1}{2} k x^{2}

mg(h +x) = \frac{1}{2} k x^{2}

By rearranging the above equation we get

k x^{2}  - 2mgx - 2mg h = 0

Put all the values in above equation we get

1500x^{2}  - 29.43 x - 26.48 = 0

By solving the above equation we get

x = 0.143 m= 14.3 cm

This is the value of the maximum distance the spring will be compressed.

8 0
3 years ago
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