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faltersainse [42]
2 years ago
12

(2a² – b) (за² + 3b)

Mathematics
1 answer:
nataly862011 [7]2 years ago
6 0

Answer:

a^4+3a^2-3b^2

Step-by-step explanation:

\hookrightarrow \: (2 {a}^{2}  - b)(3 {a}^{2}  + 3b) \\  \hookrightarrow \:2 {a}^{2} (3 {a}^{2}  + 3b) - b(3 {a}^{2}  + 3b) \\  \hookrightarrow \:6 {a}^{4}  + 6 {a}^{2} b - 3 {a}^{2} b - 3 {b}^{2} \\   \hookrightarrow \:{a}^{4}  + 3 {a}^{2} b- 3 {b}^{2}

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Multiply and simplify. 2x4yx⋅6xy2z3
OLEGan [10]

Answer:

The given expression 2x^4yx \times 6xy^2z^3   on multiplying  is 12x^6y^3z^3

Step-by-step explanation:

Consider the given two expressions 2x^4yx and 6xy^2z^3

We have multiply both expressions,

2x^4yx \times 6xy^2z^3

To multiply two terms first multiply constant numbers that is 6 × 2 = 12

For x , y and z apply property of exponent,

x^a\cdot x^b=x^{a+b}

Then power of x together will be,

x^4\cdot x\cdot x=x^{4+1+1}=x^6

Similarly for y powers,

y \cdot y^2=y^{1+2}=y^3

Since first term do not have any expression for z so it will remain same.

Thus, the given expression  on multiplying become,

2x^4yx \times 6xy^2z^3 is 12x^6y^3z^3




7 0
3 years ago
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lana [24]
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3 0
3 years ago
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den301095 [7]

Answer:

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Step-by-step explanation:

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