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Sav [38]
1 year ago
5

If the first and the last term of an arithmetic progression, with common difference

Mathematics
1 answer:
devlian [24]1 year ago
3 0

The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.

<h3>What is the nth term of an arithmetic sequence?</h3>

The general form of the nth term of an arithmetic sequence is

an = a1 + (n - 1)d

Where,

a1 - first term

n - number of terms in the sequence

d - the common difference

<h3>Calculation:</h3>

The given sequence is an arithmetic sequence.

First term a1 = 1\frac{1}{2} = 3/2

Last term an = 2\frac{1}{2} = 5/2

Common difference d = 1/9

From the general formula,

an = a1 + (n - 1)d

On substituting,

5/2 = 3/2 + (n - 1)1/9

⇒ (n - 1)1/9 = 5/2 - 3/2

⇒ (n - 1)1/9 = 1

⇒ n - 1 = 9

⇒ n = 9 + 1

∴ n = 10

Thus, there are 10 terms in the given arithmetic sequence.

learn more about the arithmetic sequence here:

brainly.com/question/503167

#SPJ1

Disclaimer: The given question in the portal is incorrect. Here is the correct question.

Question: If the first and the last term of an arithmetic progression with a common difference are 1\frac{1}{2}, 2\frac{1}{2} and 1/9 respectively, how many terms has the sequence?

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12x^2+20=50 what is x
LenaWriter [7]

Answer: x=1.5811389999999999 , or 1.59

Step-by-step explanation:

First, Subtract 20 from both sides.

      12x2+20−20=50−20

      12x2=30

 Then, Divide both sides by 12:

12x^2/12 = 30/12

⇒ you get : x^2 = 5/2

After, Take square root.

x= ± √ 5/2

Finally you answer is going to be =1.5811389999999999 OR, 1.59

* Hopefully this helps:) Mark me the brainliest:)

<em>∞ 234483279c20∞</em>

7 0
3 years ago
A car dealer has 8 rows of cars with 16 cars in each. In each of the first 3 rows, 6 are used cars. The rest of the cars new car
qwelly [4]

The answer is 110 because if you multiply 8•16=128 and 18 cars are used, you subtract 128-18 which is 110.

8 0
3 years ago
Whats the sum of 3/8 and 1/16 <br><br>a 1/6<br>b 4/24<br>c 7/16<br>d 1/4
Andreyy89
3/8 + 1/16= 7/16 
so it's c. 7/16
6 0
3 years ago
All about simulitious equations​
Korolek [52]

Answer:

On occasions you will come across two or more unknown quantities, and two or more equations

relating them. These are called simultaneous equations and when asked to solve them you

must find values of the unknowns which satisfy all the given equations at the same time.

Step-by-step explanation:

1. The solution of a pair of simultaneous equations

The solution of the pair of simultaneous equations

3x + 2y = 36, and 5x + 4y = 64

is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides

to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.

2. Solving a pair of simultaneous equations

There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a

single equation which involves the other unknown. The method is best illustrated by example.

Example

Solve the simultaneous equations 3x + 2y = 36 (1)

5x + 4y = 64 (2) .

Solution

Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation

6x + 4y = 72 (3)

Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:

6x + 4y = 72 − (3)

5x + 4y = 64 (2)

x + 0y = 8

5 0
2 years ago
The sum of a students three scores is 217. If the first is 30 points more than the the second, and the sum of the first two is 1
nekit [7.7K]

Answer:

First score is 90

Step-by-step explanation:

Let A represent the first score

Let B represent the second score

Let C represent the third score

A+B+C=217 equation 1

If the first score A is 30 points more than the second,B

A=B-30  equation 2

Lastly,sum of A&B is 16 more than 2C

A+B=2C+16 equation 3

From equation 1

A+B=217-C equation 4

substitute for A+B in equation 3

217-C=2C+16

217-16=2C+C

201=3C

C=67

substituting C in equation 4

A+B=217-67

A+B=150

if the first score more than the first,then the first 90 while second 60 since A+B=150

3 0
2 years ago
Read 2 more answers
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