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Sav [38]
1 year ago
5

If the first and the last term of an arithmetic progression, with common difference

Mathematics
1 answer:
devlian [24]1 year ago
3 0

The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.

<h3>What is the nth term of an arithmetic sequence?</h3>

The general form of the nth term of an arithmetic sequence is

an = a1 + (n - 1)d

Where,

a1 - first term

n - number of terms in the sequence

d - the common difference

<h3>Calculation:</h3>

The given sequence is an arithmetic sequence.

First term a1 = 1\frac{1}{2} = 3/2

Last term an = 2\frac{1}{2} = 5/2

Common difference d = 1/9

From the general formula,

an = a1 + (n - 1)d

On substituting,

5/2 = 3/2 + (n - 1)1/9

⇒ (n - 1)1/9 = 5/2 - 3/2

⇒ (n - 1)1/9 = 1

⇒ n - 1 = 9

⇒ n = 9 + 1

∴ n = 10

Thus, there are 10 terms in the given arithmetic sequence.

learn more about the arithmetic sequence here:

brainly.com/question/503167

#SPJ1

Disclaimer: The given question in the portal is incorrect. Here is the correct question.

Question: If the first and the last term of an arithmetic progression with a common difference are 1\frac{1}{2}, 2\frac{1}{2} and 1/9 respectively, how many terms has the sequence?

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