Answer: x=1.5811389999999999 , or 1.59
Step-by-step explanation:
First, Subtract 20 from both sides.
12x2+20−20=50−20
12x2=30
Then, Divide both sides by 12:
12x^2/12 = 30/12
⇒ you get : x^2 = 5/2
After, Take square root.
x= ± √ 5/2
Finally you answer is going to be =1.5811389999999999 OR, 1.59
* Hopefully this helps:) Mark me the brainliest:)
<em>∞ 234483279c20∞</em>
The answer is 110 because if you multiply 8•16=128 and 18 cars are used, you subtract 128-18 which is 110.
3/8 + 1/16= 7/16
so it's c. 7/16
Answer:
On occasions you will come across two or more unknown quantities, and two or more equations
relating them. These are called simultaneous equations and when asked to solve them you
must find values of the unknowns which satisfy all the given equations at the same time.
Step-by-step explanation:
1. The solution of a pair of simultaneous equations
The solution of the pair of simultaneous equations
3x + 2y = 36, and 5x + 4y = 64
is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides
to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.
2. Solving a pair of simultaneous equations
There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a
single equation which involves the other unknown. The method is best illustrated by example.
Example
Solve the simultaneous equations 3x + 2y = 36 (1)
5x + 4y = 64 (2) .
Solution
Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation
6x + 4y = 72 (3)
Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:
6x + 4y = 72 − (3)
5x + 4y = 64 (2)
x + 0y = 8
Answer:
First score is 90
Step-by-step explanation:
Let A represent the first score
Let B represent the second score
Let C represent the third score
A+B+C=217 equation 1
If the first score A is 30 points more than the second,B
A=B-30 equation 2
Lastly,sum of A&B is 16 more than 2C
A+B=2C+16 equation 3
From equation 1
A+B=217-C equation 4
substitute for A+B in equation 3
217-C=2C+16
217-16=2C+C
201=3C
C=67
substituting C in equation 4
A+B=217-67
A+B=150
if the first score more than the first,then the first 90 while second 60 since A+B=150