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Wewaii [24]
2 years ago
12

using the distance formula d=√(x2- x1)^2 +(y2-y^1, what is the distance between point (-3,1) and point (-2,4) rounded to the nea

rest tenth
Mathematics
1 answer:
defon2 years ago
4 0

Answer:

d =  \sqrt{(x2 - x1) + (y2 - y1)}  \\ d =  \sqrt{ (- 3 + 2) + (1 +  - 4)}  \\ d =  \sqrt{ - 1 +  - 3 }  \\ d =  \sqrt{ - 4 }  \\ d =  - 2

Step-by-step explanation:

<h2><em><u>hope </u></em><em><u>it </u></em><em><u>helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>
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Hlp me with this math problem
zaharov [31]

Answer:

0.5l+0.2s

Step-by-step explanation:

0.10x5<em>l</em> equals 0.5<em>l</em>

0.10x2<em>s</em> equals 0.2<em>s</em>

7 0
2 years ago
Can someone please help
choli [55]

The answer is C, 2 over 11.

There are 11 letters in Mississippi, and there is 2 p's, there fore, he has a 2 out of 11 chance to get a P.

8 0
3 years ago
Select the common denominator for 3/8 and 3/10. Check all that apply
jeka57 [31]

Answer:

common denominator is 40

Step-by-step explanation:8x5=40

10x4= 40

3x5=15

3x4=12

15/40 and 12/40

7 0
3 years ago
A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation
Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an m\times n matrix.  Let T :U\to V  be the corresponding linear transformationover the field F and \theta be identity vector in V. Now if x\in Ker( T)\implies T(x)=\theta.

(1) The kernel of a linear transformation is a vector space : True.

Let x,y\in Ker( T), then,

T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)

hence the kernel is closed under addition.

Let \lambda\in F, x\in Ker( T), then

T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta

\lambda x\in Ker(T) and thus Ket(T) is closed under multiplication

Finally, fore all vectors u\in U,

T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta

\implies \theta\in Ker(T)

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is \mathbb R^m : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in \mathbb R^m

: False

The null space that is dimension of solution space of an m x n matrix is always in \mathbb R^n.

(4) The column space of A is the range of the mapping x\to Ax

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0
3 years ago
Help Me please11111111
Y_Kistochka [10]

Answer:

The first option im pretty sure

Step-by-step explanation:

6 0
2 years ago
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