Using <span>Pythagorean theorem: c^2 = a^2 + b^2, and if a = 22 and b = 50
c^2=484+2500
c=sqrt 2984
c=55 meters</span>
see the attached figure with the letters
1) find m(x) in the interval A,BA (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100
2) find m(x) in the interval B,CB(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20
3)
find n(x) in the interval A,BA (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x
4) find n(x) in the interval B,CB(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30
5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44
6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72
for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72
<span> h'(x) = 1.44 ------------ > not exist</span>
Answer:
The second answer
Step-by-step explanation:
P'Q'R' is simply rotating PQR 90 degrees, it does not change the angle that it makes
The graph of the inequality will be B. on a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the right of the line is shaded.
<h3>How to get the graph?</h3>
It can be deduced that the coordinates satisfy the equation of the line.
3y = 2x - 12
Divide through by 3.
y = 2/3x - 4.
The slope is 2/3.
In conclusion, the correct option is B.
Learn more about inequalities on:
brainly.com/question/14074138
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We have to draw the model for 42 divide 7 . In order to draw the model we use below steps.
- Draw 7 boxes to represent 7 groups.
- Assume 42 as the number which represents the total of these 7 groups.
- Put a question mark at the first box.
Attached is the model to represents 42 divide 7 .
In the question mark we should put 6. Hence, when we add 6 to 7 times that will be equal to 42.