The answer your looking for is 30
30 ÷ 5 = 6
Answer: h(x) = 3*x^2 - 7*x + 8
Step-by-step explanation:
The rate of change of a function is equal to the derivate:
remember that a derivate of the form:
k(x) = a*x^n is k'(x) = n*a*x^(n-1)
Then we have:
f(x) = 2*x - 10
f'(x) = 1*2* = 2
g(x) = 16*x - 4
g'(x) = 1*16 = 16
h(x) = 3*x^2 - 7*x + 8
h'(x) = 2*3*x - 1*7 = 6*x - 7
So the only that increases as x increases is h(x), this means that the greates rate of change as x approaches inffinity is the rate of change of h(x)
Answer:
x = 2.81 and 2.096
Step-by-step explanation:
Given the expression
10(2^x) + 7(3^x) = 6^x + 70
This can also be expressed as;
10(2^x) + 7(3^x) = (2*3)^x + 70
10(2^x) + 7(3^x) = 2^x*3^x + 70
Let a = 2^x and b = 3^x
10a + 7b = ab + 70
10a + 7b - ab = 70
10a-ab + 7b - 70 = 0
a(10-b)+7(b-10) = 0
a(10-b)-7(10-b) = 0
a-7 = 0 and 10-b = 0
a = 7 and b = 10
Since a = 2^x
7 = 2^x
log 7 = log2^x
log7 = xlog2
x = log7/log2
x = 2.81
Similarly
10 = 3^x
log 10 = log 3^x
log 10 = xlog3
x = log 10/log 3
x = 1/0.4771
x = 2.096
Hence the values of x that satisfies the equation are 2.81 and 2.096
Here ya go. Hope this helps. Have a great day
I would be able to but i left my maths book at school and that has the explanation in, sorry :(
