A lamppost is 12 feet high and casts a
1 answer:
You might be interested in
Answer:
∠ADB = γ/2 +90°
Step-by-step explanation:
Here's one way to show the measure of ∠ADB.
∠ADB = 180° - (α + β) . . . . . sum of angles in ΔABD
∠ADB + (2α +β) + γ + (2β +α) = 360° . . . . . sum of angles in DXCY
Substituting for (α + β) in the second equation, we get ...
∠ADB + 3(180° - ∠ADB) + γ = 360°
180° + γ = 2(∠ADB) . . . . . . add 2(∠ADB)-360°
∠ADB = γ/2 + 90° . . . . . . . divide by 2
_____
To find angles CXD and CYD, we observe that these are exterior angles to triangles AXB and AYB, respectively. As such, those angles are equal to the sum of the remote interior angles, taking into account that AY and BX are angle bisectors.
