The answer is : B. (X-10)(x-4)
Answer:
50
Step-by-step explanation:
I'm sorry but your missing the questions but I found a close answer! Let A be the number of cards Alan has B be the number of cards Bill has C be the number of cards Calvin has Alan had 11 less than 2 1/2 times the number of cards bill has. is 2.5 Alan is 2.5 of bill has minus 11 A=2.5B -11 Calvin has 1 more than 1 1/2 times the number of cards bill has. is 1.5 Calvin is 1.5 of bill has plus 1 C=1.5B + 1 Alan and Calvin have the same number of cards So A=C WE plug in A and C equations and solve for B 2.5B -11 = 1.5B + 1 (subtract 1.5B on both sides) 1B -11 = 1 (Add 11 on both sides) B = 12 If Alan and Calvin have the same number of cards, the number bill has is 12 The number of cards Alan and Calvin each have is 19 Total cards = 12 + 19 + 19 = 50 If Alan, bill, and Calvin have all the cards in the deck then the deck has 50 cards.
If you draw the line and mark -2 and 3 you find that they are 5 apart. By calculation, subtract the lowest from the highest: 3 - -2 = 3+2 = 5
Answer:
Step-by-step explanation:
Let x represent the number of attendees that it will take the company to break even.
The company pays a flat fee of $98 to rent a facility in which to hold each session. Additionally, for every attendee who registers, the company must spend $16 to purchase books and supplies. This means that the total cost that the company would pay for x attendees is
16x + 98
Each attendee will pay $65 for the seminar. This means that the total revenue that the company would generate from x attendees is 65x.
At the break even point,
total cost = total revenue
Therefore,
16x + 90 = 65x
65x - 16x = 98
49x = 98
x = 98/49
x = 2
It will take 2 attendees and the total expenses and revenues is
2 × 65 = $130
