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3 years ago

4. Can two lines be parallel and perpendicular? Explain.

Mathematics

1 answer:

lidiya [134]3 years ago

7 0

Answer: No

Step-by-step explanation: First, we need to understand that parallel lines are coplanar lines that do not intersect. On the other hand, perpendicular lines are lines that intersect at a right angle.

However, lines can't be both parallel and perpendicular because they either intersect each other at a right angle or never intersect.

So no, two lines can't be both parallel and perpendicular.

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How do you put 3y+x=12 in y=mx+b form

dezoksy [38]

3y+x=12 in slope intercept form is y=-1/3+4

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3 years ago

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Bill and Joe both want to finance a new car. for the following scenario identify which one would be more likely to qualify for a

Vladimir [108]

Answer:

Joe is likely to get a low interest rate because paying your bills on time helps build a good credit.

Step-by-step explanation:

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3 years ago

Kendell made 2/5 of a necklace in 1/9 of an hour. How many necklacws can she make in one hour?

Ivahew [28]

Answer:

18/5 or 36 necklace

Step-by-step explanation:

kendell made 2/5 necklace in 1/9 hours

how many will she make in 1 hour

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2/5 × 1 = 1/9x

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2 years ago

√(25 - 10 √(3) + 3) (not as a decimal)

nikitadnepr [17]

Answer:

$\huge\boxed{\sqrt{25-10\sqrt3+3}=5-\sqrt3}$

Step-by-step explanation:

$\sqrt{25-10\sqrt3+3}=(*)\\\\25=5^2\\3=(\sqrt3)^2\\10\sqrt3=(2)(5)(\sqrt3)\\\\(*)=\sqrt{5^2-(2)(5)(\sqrt3)+(\sqrt3)^2}\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=\sqrt{(5-\sqrt3)^2}\\\\\text{use}\ \sqrt{a^2}=|a|\\\\=|5-\sqrt3|=5-\sqrt3\\\\^{\text{because}\ 5>\sqrt3\to5-\sqrt3>0}$

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3 years ago

assume the substance has a half-life of 11 years and the initial amount is 126 grams.How long will it be until only 15 % remains

Mumz [18]

(126) times (1/2 to the x/11 power) = 15% times 126

(1/2) to the x/11 power = 0.15

Take the log of both sides :

(x/11) times log(1/2) = log(0.15)

Multiply both sides by 11 :

'x' times log(1/2) = 11 x log(0.15)

Divide both sides by " log(1/2) " :

x = 11 x log(0.15)/log(1/2) = 30.107 years (rounded)

That's the time it takes for any-size sample of this substance
to decay to 15% of its original size.

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3 years ago