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3 years ago

7

How do u find the perimeter and the area of a triangle with the hypotenuse of 25 cm and leg 20 cm

1 answer:

Arada [10]3 years ago

4 0

Our triangle is ABC with ∠C = 90°

1) AB² = BC² + AC² (Pythagorean theorem)
25² = 20² + AC²
AC² = 625 - 400
AC² = 225
AC = 15
2) PΔABC = AB + BC + AC = 25 + 15 + 20 = 60
3) SΔABC = AC * BC * 1/2 = 15 * 20 * 1/2 = 150

Answer: the perimeter is 60 cm and the area is 150 cm² .

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Answer:

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Step-by-step explanation:

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Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

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$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

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$=\frac{1}{\sqrt{20}}$

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Answer:

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Step-by-step explanation:

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