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USPshnik [31]
2 years ago
15

Find each of the angle measures of the polygon with the angles of (x-5) (x+35) 1.4x and x

Mathematics
1 answer:
Klio2033 [76]2 years ago
4 0
Tbh I’m not good at math so sorry. But we can try that’s again. So it would be 24-59
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(125,75)-(40,72) işleminin sonucunu bulunuz​
V125BC [204]

85,03 çevap budur inşallah doğrudur iyi dersler

8 0
2 years ago
Allison, Brianna, and Celeste went on a hike. Allison brought 9 homemade
poizon [28]

Answer:

Allison = $0.27

Brianna = $1.89

Step-by-step explanation:

The total cookies that the three girls have are:

Allison's cookies + Brianna's Cookies

= 9+15

=24

There is a total of 24 cookies which has to be divided between the 3.

So

Each girl gets 24/3 = 8 cookies.

Since Celeste had no cookies she will have to pay for the 8 cookies.

Allison had 9, she will give one to Celeste

Brianna had 15 out of which she will use 8 for her self and 7 will be given to Celeste.

Celeste is paying 2.16 for 8 cookies.

Price of one cookie = 2.16/8

=$0.27

So, amount that will be given to Allison = 0.27 * 1 = $0.27

Amount that will be given to Brianna = 0.27 * 7 = $1.89

6 0
2 years ago
he yearbook club had a meeting. The meeting had 24 people, which is three-fourths of the club. How many people are in the club
WINSTONCH [101]

Answer:

32 people

Step-by-step explanation:

If 3/4 equals 24, we need to find the other fourth. We can divided the total number of people by the numerator. 24/8, then add 8, which equals 32.

4 0
3 years ago
WILL MAKE BRAINLIEST !!!!! The equation y = 35.25x + 40 gives the labor cost y of repairing a car if takes x hours to repair the
seraphim [82]
Y = $35.25(6) + 40

y = $211.5 + $40= $251.50

the answer is a
5 0
3 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
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