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USPshnik [31]
3 years ago
15

Find each of the angle measures of the polygon with the angles of (x-5) (x+35) 1.4x and x

Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0
Tbh I’m not good at math so sorry. But we can try that’s again. So it would be 24-59
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James has 36 tulips and needs to have same number in each vase
maks197457 [2]

Use the <u>factor pairs</u> of 36.  You'll find that he has
9 different ways to arrange them:

<em>1 x 36</em> ... 1 tulip each in 36 vases, or 36 tulips in1  vase

<em>2 x18</em> ... 2 tulips each in 18 vases, or 18 tulips each in 2 vases

<em>3 x 12</em> ... 3 tulips each in 12 vases, or 12 tulips each in 3 vases

<em>4 x 9</em> ... 4 tulips each in 9 vases, or 9 tulips each in 4 vases

<em>6 x 6</em> ... 6 tulips each in 6 vases


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Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

6 0
3 years ago
PLEASE HELP!!!!!!!<br><br><br><br>Use an equation to find the value of each indicated variable.
Irina18 [472]

Answer:

y=36°

z=54°

Step-by-step explanation:

3y+2y -> 5y=180 y=36

90-36= 54

5 0
4 years ago
How do I solve this????
Arlecino [84]
Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater

so "b" is "4 more than 5 times" "a"

so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4

so.. whatever "a" is, "b" is 5a+4

now, their sum is 22, as opposed to "zz" hehe

so       \bf \begin{cases}&#10;a+b=22\\&#10;--------------\\&#10;\boxed{b}=5a+4\qquad thus\\&#10;--------------\\&#10;a+\boxed{5a+4}=22&#10;\end{cases}

solve for "a", to see what the smaller one is

what's "b"?  well, b = 5a + 4
3 0
3 years ago
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