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nikklg [1K]
2 years ago
10

Plot and connect the points A (2, -2), B (-4, -4), C (-4, -1), D (-2, 3), E (1, 3), F (2, 5), and find the length of BC.

Mathematics
2 answers:
ankoles [38]2 years ago
8 0
  • B(-4,-4)
  • C(-4,-1)

Distance

  • √(x_2-x_1)^2+(y_2-y_1)^2
  • √(-4+4)^2+(-1+4)^2
  • √3²
  • 3 units

Graph is attached

Paul [167]2 years ago
6 0

Answer:

BC = 3 units

Step-by-step explanation:

Given points:

  • A = (2, -2)
  • B = (-4, -4)
  • C = (-4, -1)
  • D = (-2, 3)
  • E = (1, 3)
  • F = (2, 5)

<u>Plot the points</u> on the coordinate plane (x, y) and connect them in alphabetical order with straight lines (see attached).

From visual inspection of the <u>drawn polygon</u>, we can see that the length of BC is 3 units.

It is fairly simple to calculate the length of BC without plotting the points.

As points B and C have the same x-value, this means that the distance between them is simply the difference between their y-values.

⇒ distance = |-4 - (-1)| = |-3| = 3 units

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Yan na po
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3 years ago
Write and solve the sentence as an inequality.<br> A number minus 3 is less than -5.
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Answer:

x - 3 < -5 is the inequality x < -2 is the solution

Step-by-step explanation:

x - 3 < -5

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5 0
3 years ago
HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing. Check ALL that apply.
Elena L [17]

Answer:

x = -2 or x = 1/3 thus: B & C

Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 + 7 x - 2 = 2 x - x^2

Subtract 2 x - x^2 from both sides:

3 x^2 + 5 x - 2 = 0

The left hand side factors into a product with two terms:

(x + 2) (3 x - 1) = 0

Split into two equations:

x + 2 = 0 or 3 x - 1 = 0

Subtract 2 from both sides:

x = -2 or 3 x - 1 = 0

Add 1 to both sides:

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The junior and senior students at Mathville High School are going to present an exciting musical entitled, "Math, What is it Goo
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Some parts are missing in the queston. Find attached the picture with the complete question

Answer:

                   \large\boxed{\large\boxed{161}}

Explanation:

Let's put the information in a table step-by step.

                                                (number of remaining students)

                                                        Juniors          Seniors

Condition

  • Initially                                           J                     S
  • 15 seniors left                                                   S - 15
  • Twice juniors as seniors         2(S - 15)
  • 3/4 of the juniors left              1/4×2(S - 15)
  • 1/3 of seniors left                                             2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

  • 2/3×(S - 15) -  1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

2/3\times (S - 15) -  1/4\times 2(S - 15) = 8

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  • Distribution property:

8S-120-6S-90=96

  • Addtion property of equalities:

8S-6S=96+120+90

  • Add like terms:

2S=306

  • Division property of equalities:

S=306/2=153

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

2/3\times (S-15)+1/4\times 2(S-15)

Just substitute S with 153 fo find the number of students that remained to perfom in the musical:

          2/3\times (153-15)+1/4\times 2(153-15)\\ \\ 2/3(138)+1/2(138)

          161

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