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Mila [183]
2 years ago
11

What is the vertex form of the quadratic function that has a vertex at (4,3)

Mathematics
1 answer:
Ket [755]2 years ago
3 0
The answer is the letter c.
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Ill give brainliest - please help ASAP<br><br> WITH THE WORK THO PLEASE?
ohaa [14]

Answer:

5.

we have.

11x=½(16x+16+50)

22x=16x+66

22x-16x=66

6x=66

x=66/6

x=11

6.

118°=½(6x-11+181)

236=6x+170

6x=236-170

x=66/6

x=11°

7.

34°=½(arcAK-arc LN)

34×2=(110-arc LN)

arc LN =110-68

arc LN=42°

8.

<L=½(arc EN-arc KM)

<L=½(139°-73°)

<L=33

4 0
3 years ago
What postulate or theorem can be used to prove that ΔEFG ≅ ΔJHG?
OlgaM077 [116]
The answer Is C: SAS Congruence Postulate.
6 0
3 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
antoniya [11.8K]

Answer:

It's answer is 8

Step-by-step explanation:

hypotenuse (h) = 10

base (b) = 6

perpendicular (p) = x = ?

We know by using Pythagoras theorem

p = √ h² - b²

= √ 10² - 6²

= √ 100 - 36

= √ 64

x = 8

Hope it will help : ) ❤

3 0
2 years ago
What is the area of a regular nonagon (9 sides) with side length of 15 cm and apothem of 20.6 cm? Round the answer to the neares
Triss [41]
We know that

<span>The nine radii of a regular Nonagon divides into 9 congruent isosceles triangles
</span>therefore
[the area of <span>a regular nonagon]=9*[area of isosceles triangle]

</span>[area of isosceles triangle]=b*h/2------> 15*20.6/2----> 154.5 cm²
so
[the area of a regular nonagon]=9*[154.5]------> 1390.5 cm²

the answer is
1390.5 cm²

5 0
3 years ago
The table shows values for functions f(x) and g(x). x f(x)=2x−3 g(x)=73x−2 −1 −52 −133 0 −2 −2 1 −1 13 2 1 83 3 5 5 4 13 223 5 2
Verizon [17]

0 and 2

f(x) = g(x) will be the input or x value at which f and g have the same output or y value. Look in the table where two numbers repeat right next to each other.

−1 −7/2 −9/2

0 −3 −3

1 −2 −3/2

2 0 0

3 4 3/2

4 12 3

5 28 9/2

There are two solutions to f(x) = g(x) which are x=0 and x=2.

6 0
3 years ago
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