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alukav5142 [94]
3 years ago
9

Select the proper inverse operation to check the answer to 25 - 13 = 12.

Mathematics
1 answer:
Illusion [34]3 years ago
3 0
D. 12 + 13 = 25,

Why you ask? Because the inverse operation of addition is subtraction.

Hope this Helps!!!
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What is the constant rate of change for this equation y = 1/9x-20 ?​
k0ka [10]

Answer:

like:-

1/9x20 = <u>2 2/9</u>

1/9-20 = <u>19 8/9 </u>

Step-by-step explanation:

<h3><u>I'm not sure</u></h3>

3 0
2 years ago
Read 2 more answers
Question 1<br> 2 (4x - 1) + 6<br> Equivalent to what
WARRIOR [948]

Answer:

2 (4x - 1) + 6 = 8x + 4 = 4(2x+1)

Step-by-step explanation:

2 (4x - 1) + 6

= (2*4x + 2*-1) + 6

= 8x - 2 + 6

= 8x + 4

= 4/(2x+1)

8 0
2 years ago
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Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of op
Anika [276]

Answer:

The probability that the maximum speed is at most 49 km/h is 0.8340.

Step-by-step explanation:

Let the random variable<em> </em><em>X</em> be defined as the maximum speed of a moped.

The random variable <em>X</em> is Normally distributed with mean, <em>μ</em> = 46.8 km/h and standard deviation, <em>σ</em> = 1.75 km/h.

To compute the probability of a Normally distributed random variable we first need to convert the raw score of the random variable to a standardized or <em>z</em>-score.

The formula to convert <em>X</em> into <em>z</em>-score is:

z=\frac{X-\mu}{\sigma}

Compute the probability that the maximum speed is at most 49 km/h as follows:

Apply continuity correction:

P (X ≤ 49) = P (X < 49 - 0.50)

                = P (X < 48.50)

                =P(\frac{X-\mu}{\sigma}

*Use a <em>z</em>-table for the probability.

Thus, the probability that the maximum speed is at most 49 km/h is 0.8340.

8 0
3 years ago
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
3 years ago
5s-(100+2s =4s-2(10+s) how much boxes would they need to sell to get a equal amount each group must sell to have equal profits.
antoniya [11.8K]
5s-100-2s=4s-20-2s
3s-100. = 2s-20
+20. +20
3s-80. = 2s
-3s. -3s
-80. = -1s
-1 -1
80. = s

s=80
6 0
3 years ago
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