Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2). calculate the concentration of solute
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Answer:
25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.
Explanation:
The balanced reaction is:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
- C₂H₂: 2 moles
- O₂: 5 moles
- CO₂: 4 moles
- H₂O: 2 moles
The molar mass of each compound is:
- C₂H₂: 26 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- C₂H₂: 2 moles* 26 g/mole= 52 g
- O₂: 5 moles* 32 g/mole= 160 g
- CO₂: 4 moles* 44 g/mole= 176 g
- H₂O: 2 moles* 18 g/mole= 36 g
Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?
mass of O₂= 25.08 grams
<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>
LiAlH₄ is used as strong reducing agent. The hydride produced acts as a nucleophile and attacks the electrophillic carbon of carbonyl group. In given example two reactions are observed.
Reaction 1:
In first step LiAlH₄ when treated with Ester produces corresponding Aldehyde and alcohol.
Reaction 2:
This aldehyde produced further reacts with LiAlH₄ to give a reduced product (Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
Reaction 1:
In first step LiAlH₄ when treated with Ester produces corresponding Aldehyde and alcohol.
Reaction 2:
This aldehyde produced further reacts with LiAlH₄ to give a reduced product (Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,