Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2), then the concentration of solute s in hexane if [s]water is 0. 011 m is 0.055m.
<h3>What is partition Coefficent?
</h3>
It is defined as the ratio of the concentration of solute in two immiscible ( or slightly miscible liquid) in two solids, when they are in equilibrium across the interface between them.
<h3>What is concentration?</h3>
It is defined as the ratio of number of moles of compound to the volume of compound.
Solute S has a partition coefficient of 5 between water and hexane
Partition coefficient Kd = 5.0
Now we calculate the concentration of S in hexane
[hexane]/[water] = Kd
[Hexane]= 5.0 × (water)
[Hexane] = 5 × (0. 011)
[Hexane] = 0.055 m
Thus, we found that the concentration of solute of hexane if water is 0.011m is 0.055m.
learn more about concentration:
brainly.com/question/14803618
#SPJ4
