Predict the major organic product formed when the compound shown below undergoes a reaction with lialh4. draw only the product w
ith the longest chain of contiguous c atoms.
1 answer:
LiAlH₄ is used as strong reducing agent. The hydride produced acts as a nucleophile and attacks the electrophillic carbon of carbonyl group. In given example two reactions are observed.
Reaction 1:
In first step LiAlH₄ when treated with Ester produces corresponding Aldehyde and alcohol.
Reaction 2:
This aldehyde produced further reacts with LiAlH₄ to give a reduced product (Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
Reaction 1:
In first step LiAlH₄ when treated with Ester produces corresponding Aldehyde and alcohol.
Reaction 2:
This aldehyde produced further reacts with LiAlH₄ to give a reduced product (Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
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Answer:
(a) 0.294 mol silver =
(b) 8.98 * 10-3 mol sodium chloride -
(c) 23.3 mol carbon dioxide =
(d) 0.310 mol nitrogen (N2) =
Explanation:
In one mole there are atoms/molecules
(a) 0.294 mol silver =
(b) 8.98 * 10-3 mol sodium chloride -
(c) 23.3 mol carbon dioxide =
(d) 0.310 mol nitrogen (N2) =
Answer:
%age Yield = 85.36 %
Solution:
The Balance Chemical Reaction is as follow,
C₆H₁₂O + Acid Catalyst → C₆H₁₀ + Acid Catalyst + H₂O
According to Equation ,
100 g (1 mole) C₆H₁₂O produces = 82 g (1 moles) of C₆H₁₀
So,
4.0 g of C₆H₁₂O will produce = X g of C₆H₁₀
Solving for X,
X = (4.0 g × 82 g) ÷ 100 g
X = 3.28 g of C₆H₁₀ (Theoretical Yield)
As we know,
%age Yield = (Actual Yield ÷ Theoretical Yield) × 100
%age Yield = (2.8 g ÷ 3.28 g) × 100
%age Yield = 85.36 %
