The scale will read <u>112 grams.</u>
Why?
Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:
We can see that the scale will read 112 grams.
Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:
Hence, we can see that the scale will read <u>112 grams.</u>
Have a nice day!
All of them are important to identify a mineral and get information from it, but I'd say the least important is cleavage.
Answer:
Bohr thought that electrons orbited the nucleus in quantised orbits. ... In Rutherford's model most of the atom's mass is concentrated into the centre (what we now call the nucleus) and electrons surround the positive mass in something like a cloud. Bohr's most significant contribution was the quantisation of the model.
Explanation:
The least amount of energy required to activate atoms or molecules to a state in which they can undergo a chemical reaction.
Answer:
If n=1, l can only have the value l=0 and the total number of orbitals is 0. If l=1, ml can be -1,0 or 1 and the total number of orbitals at l=1 is 3.
Explanation:
When solving the radial part of Schrödinger equation, one needs to expand in power series that lead to Laguerre polynomials of the form , being n and l the quantum numbers. As is known, in the Laguerre polynomials the subindex must be greater than or equal to 0, which implies . So if n=1, the only possible value of l is l=0.
Likewise, when solving the angular part, one gets the spherical harmonics can be . Therefore the sublevel l=| has 3 possible orbitals.