The numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.
Since a furniture company has 480 board ft of teak wood and can sustain up to 450 hours of labor each week, and each chair produced requires 8 ft of wood and 12 hours of labor, and each table requires 20 ft of wood and 15 hours of labor, to determine, if a chair yields a profit of $ 65 and a table yields a profit of $ 90, what are the numbers of chairs and tables that should be produced each week in order to maximize the company's profit, the following calculation should be done:
- 16 chairs; 24 tables
- Time used = 16 x 12 + 24 x 15 = 192 + 360 = 552
- Wood used = 16 x 8 + 24 x 20 = 128 + 480 = 608
- 15 chairs; 18 tables
- Time used = 15 x 12 + 18 x 15 = 180 + 270 = 450
- Wood used = 15 x 8 + 18 x 20 = 120 + 360 = 480
- 12 chairs; 28 tables
- Time used = 12 x 12 + 28 x 15 = 144 + 420 = 564
- Wood used = 12 x 8 + 28 x 20 = 96 + 540 = 636
- 18 chairs; 20 tables
- Time used = 18 x 12 + 20 x 15 = 216 + 300 = 516
- Wood used = 18 x 8 + 20 x 20 = 144 + 400 = 544
Therefore, the only option that meets the requirements of time and wood used is that of 15 chairs and 18 tables, whose economic benefit will be the following:
- 15 x 65 + 18 x 90 = X
- 975 + 1,620 = X
- 2,595 = X
Therefore, the numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.
Learn more in brainly.com/question/14728529
Answer:
0.992
Step-by-step explanation:
do you not have a calculator
Answer:
A = P (1 + rt)
A = final amount
P = initial principal balance
r = annual interest rate
t = time (in years)
Step-by-step explanation: brainliest plz
Answer:
-2/9
Step-by-step explanation:
The slope is found by
m= (y2-y1)/(x2-x1)
= (-12- -14)/(3-12)
=(-12+14)/(3-12)
=2/-9
= -2/9
A.) P(t) = P0exp(kt)
P(20/60) = 40 exp(20k/60)
80 = 40 exp(k/3)
exp(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)
b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells
d.) Rate of change = exp(8k) = exp(8(3ln(2)) = exp(24ln(2)) = exp(16.6355) = 16777216 cells / hour
e.) P(t) = 40(2)^3t; t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours