Because sometimes the only multiple of each number that is in both numbers. 1 and the number. 3 and 5. Multiples are (1 and 3) and (1 and 5).
Answer: Their total budget last year was $40,000.
Step-by-step explanation:
Given : The Smiths spend 6% of their budget on entertainment.
i.e. , The money they spend on entertainment = 0.06 x ( Total budget)
{ 6% is converted to 0.06 , when we divide it by 100 to remove percentage)
Since , this year they plan to spend $2,580 on entertainment.
i.e. 0.06 x ( Total budget ) = $2,580
On dividing both sides by 0.06 , we get
( Total budget ) = $2,580 ÷ 0.06
= $43,000
Thus , their total budget for this year = $43,000
Also, Their total budget this year is $3,000 more than last year.
Therefore , their last year total budget = ( Total budget this year ) - $3000
= $43,000 - $3000
= $40,000
Hence, their total budget last year was $40,000.
Hope this helps! Also can I have brainliest? It’s ok if no :) have a nice day.
Answer:
it is a right triangle
Step-by-step explanation:
i have no explanation my sister told me with no explanation sorry
7
Clocks can display up to the number 59 (60 minutes in an hour). If you list all of the perfect squares that are under 59, you will find that there is 7 of them: 1, 4, 9, 16, 25, 36, and 49.
Answer:
Step-by-step explanation:
REcall the following definition of induced operation.
Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.
So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.
For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).
Case SL2(R):
Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So
.
So AB is also in SL2(R).
Case GL2(R):
Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So
.
So AB is also in GL2(R).
With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).