Answer: cleft grafting, inlay grafting, four-flap grafting, and whip grafting.
Explanation:
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Answer:
solution
we know that .
s=ut+½at²
now, putting the values in the second equation of motion ,
we get,
S=20×10+1/2×(10)²
S=200+1×100
S=200+100
S=300m
the distance covered by given body or object in 10 seconds is 300 m.
Answer:
179.655m
Explanation:
Given
Maximum speed of the arrow v = 60m/s
Time taken to hit the top of the cliff t = 7.0s
Required
Height of the cliff H
Using the equation of motion
H = vt + 1/2gt²
Substitute into the formula:
H = 60(7) + 1/2 (-9.81)(7²) (g is negative due to upward motion of the arrow)
H = 420-4.905(49)
H = 420-240.345
H = 179.655m
Hence the cliff is 179.655m high
Force is mass into acceleration
and pressure is force applied per unit area.