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3 years ago

The speed of molecules is indirectly related to a measurement called _____.

Physics

2 answers:

Lubov Fominskaja [6]3 years ago

6 0

Answer : (c) temperature is the correct option.

Explanation :

The speed of molecules is directly proportional to temperature. If the temperature of the system is increased, the molecules start vibrating i.e. their kinetic energy increases which in turn increase its velocity.

From kinetic theory of gases,

$v_{rms}=\sqrt{\dfrac{3\ RT}{M}}$ ........(1)

where,

R is the gas constant

T is temperature

M is molar mass

So, from equation (1) it is clear that velocity is directly proportional to temperature.

Hence, the correct option is (B) " temperature"

seraphim [82]3 years ago

4 0

The average speed of all the molecules in an object
or sample of a substance is related to its temperature ...
and not indirectly at all.

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3 years ago

A wooden object (conically shaped) has a diameter of 8cm and height of 14cm. It floats in oil with 6cm of its height above oil l

baherus [9]

Answer:

(a) The density of the object is 316/343 × the density of the oil

(b) The fraction of oil displaced after immersing the object is 0.461 of the oil volume

Explanation:

(a) The volume, V of a cone of height, h and base diameter, D = 2×r is given by the following equation;

$V = \dfrac{\pi r^{2} h}{3}$

The volume of the object is therefore;

$\dfrac{\pi \times 4^{2} \times 14}{3} = 74\tfrac{2}{3}\pi \, cm^3$

Where 6 cm is above the oil level we have;

$\dfrac{\pi \times \left (6 \times \dfrac{4}{14} \right )^{2} \times 6}{3} = 5\tfrac{43}{49}\pi \, cm^3$ above the oil level

Therefore, volume of the oil displaced = $68\tfrac{116}{147}\pi$ cm³ = 216.11 cm³

The density of the object is thus;

$\dfrac{68\tfrac{116}{147}\pi}{ 74\tfrac{2}{3}\pi} \times Density \ of \ the \ oil = \dfrac{316}{343} \right ) \times Density \ of \ the \ oil$

The density of the object = 316/343 × the density of the oil.

(b) The volume of the oil = 2 × Volume of the object = $2 \times 74\tfrac{2}{3}\pi \, cm^3 = 149\tfrac{1}{3}\pi \, cm^3$

The fraction of the volume displaced, x, after immersing the object is given as follows;

$x = \dfrac{68\tfrac{116}{147}\pi}{ 149\tfrac{1}{3}\pi} = \dfrac{158}{343} = 0.461$

The fraction of oil displaced after immersing the object = 0.461 of the volume of the oil

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3 years ago

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2 years ago

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Answer:

Explanation:

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