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AlladinOne [14]

3 years ago

5

A 90.0kg person stands 1.25m from a 60.0kg person sitting on a bench nearby. What is the magnitude of the gravitational force be

tween them ?

1 answer:

VashaNatasha [74]3 years ago

7 0

Answer: $23(10)^{-8} N$

Explanation:

According to Newton's law of Gravitation, the force $F$ exerted between two bodies of masses $m1$ and $m2$ and separated by a distance $r$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{(m1)(m2)}{r^2}$ (1)

Where:

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational Constant

$m1=90 kg$ is the mass of the first person

$m2=60 kg$ is the mass of the second person

$r=1.25 m$ is the distance between both persons

Solving:

$F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(90 kg)(60 kg)}{(1.25 m)^2}$ (2)

Finally:

$F=23(10)^{-8} N$ This is the gravitational force between both persons. As you can see is too small.

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The velocity of any wave is given by:

$v=f \lambda$

In which $f$ is the wave's frequency (measured in hertz) and $\lambda$ is the wave's wavelength (measured in meters).

So, for this wave:
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3 years ago

To understand the concept of intensity; the relationship between the power of the source and the intensity of the wave; and the

frez [133]

Answer:

a. <em>4.77 </em>W/ $m^{2}$

b. 2.122 W/ $m^{2}$

c. <em>13.78</em> W/ $m^{2}$

d. <em>69 km</em>

Explanation:

a.

power P of speaker = 60 W

distance d of speaker = 1.0 m

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I = 60/(4 x 3.142 x $1^{2}$ ) = 60/12.568

Intensity = <em>4.77 </em>W/ $m^{2}$

b.

at a distance of 1.5 m, intensity will be

I = P/4π $d^{2}$

I = 60/(4 x 3.142 x $1.5^{2}$ ) = 60/28.278

Intensity = 2.122 W/ $m^{2}$

c.

combined intensity of the two front speakers will be 2 x 4.77 = 9.54 W/ $m^{2}$

combined intensity of the two back speaker will be 2 x 2.122 = 4.244 W/ $m^{2}$

<em>total sound intensity perceived by the driver will be the superimposition of these four speakers.</em>

I = 9.54 + 4.244 =<em> 13.78</em> W/ $m^{2}$

d.

Minimum discernible intensity of sound = $10^{-12}$ W/ $m^{2}$

each speaker produces 0.06 W of power.

<em>We assume that each speaker spreads outward evenly.</em>

from<em> I = P/4π</em> $d^{2}$ <em>,</em>

d = $\sqrt{\frac{P}{4*\pi*I } }$

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3 years ago

An electron traveling horizontally to the right enters a region where a uniform electric field is directed downward. What is the

astraxan [27]

Answer:

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- if the particle is positively charged, the direction of the force is the same as the direction of the electric field

- if the particle is negatively charged, the direction of the force is opposite to the direction of the electric field

In this problem, we have an electron - so a negatively charged particle - so the direction of the force is opposite to that of the electric field.

Since the electric field is directed downward, therefore, the electric force on the electron will be upward.

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2 years ago

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3 years ago

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Answer:

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