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Katyanochek1 [597]
3 years ago
11

Name the group of galaxies of which the Milky Way is a member?

Physics
2 answers:
xxTIMURxx [149]3 years ago
5 0

Answer:

The Local Group

Explanation:

The Milky Way galaxy is one of more than 54 galaxies known as the Local Group. The three largest members of the group are our Milky Way (second-biggest), the Andromeda galaxy (biggest) and the Triangulum Galaxy. <em>(earthsky)</em>

Natasha2012 [34]3 years ago
5 0

Answer:

the milky way is 54 galaxies so it fits in

The local group

Explanation:

hope that helps>3

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When a river flows into an ocean, it slows down and deposits materials in its delta
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3 years ago
A spherical balloon has a radius of 6.55 m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of a
Ksju [112]

Answer:

M_1 = 317.7 kg

Explanation:

Mass of the helium gas filled inside the volume of balloon is given as

m = \rho V

m = 0.179(\frac{4}{3}\pi R^3)

m = 0.179(\frac{4}{3}\pi 6.55^3)

m = 210.7 kg

now total mass of balloon + helium inside balloon is given as

M = 210.7 + 990

M = 1200.7 kg

now we know that total weight of balloon + cargo = buoyancy force on the balloon

so we will have

(M + M_1)g = \rho_{air} V g

(1200.7 + M_1) = (\frac{4}{3}\pi 6.55^3) (1.29)

1200.7 + M_1 = 1518.4

M_1 = 317.7 kg

3 0
3 years ago
A ball is dropped from a tower that is 206 m high, How long does it take to reach the ground?
Slav-nsk [51]

It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.

From the question given above, the following data were obtained:

Height (H) = 206 m

<h3>Time (t) =? </h3>

NOTE: Acceleration due to gravity (g) = 10 m/s²

The time taken for the ball to get to the ground can be obtained as follow:

H = ½gt²

206 = ½ × 10 × t²

206 = 5 × t²

Divide both side by 5

t^{2}  = \frac{206}{5}\\\\ t^{2} = 41.2

Take the square root of both side

t = \sqrt{41.2}

<h3>t = 6.42 s</h3>

Therefore, it will take 6.42 s for the ball to get to the ground.

Learn more: brainly.com/question/24903556

7 0
3 years ago
Using the law of conservation of angular momentum, estimate how fast a collapsed stellar core would spin if its initial spin rat
Nataly_w [17]

Answer:

\omega_{f} = 1000000\,\frac{rev}{day}

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\frac{2}{5}\cdot M\cdot R_{o}^{2} \cdot \omega_{o} = \frac{2}{5}\cdot M\cdot R_{f}^{2} \cdot \omega_{f}

The final angular speed is:

\omega_{f} = \omega_{o}\cdot (\frac{R_{o}}{R_{f}})^{2}

\omega_{f} = (1\,\frac{rev}{day} )\cdot (\frac{10000\,km}{10\,km} )^{2}

\omega_{f} = 1000000\,\frac{rev}{day}

3 0
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How do you think heat gets from a filament to the kernel?​
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Answer:

Explanation:

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