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1 year ago

The slope-intercept form given (6,-5) & perpendicular to -5x - 7y = -17.

Mathematics

1 answer:

tatuchka [14]1 year ago

8 0

Answer:

$y=\dfrac{7}{5}x-\dfrac{67}{5}$

Step-by-step explanation:

Slope-intercept form of a linear equation:

$y=mx+b$

where:

m is the slope.
b is the y-intercept.

Rearrange the given equation so that it is in slope-intercept form:

$\implies -5x-7y=-17$

$\implies -7y=5x-17$

$\implies y=-\dfrac{5}{7}x+\dfrac{17}{7}$

Therefore, the slope of the given equation is -⁵/₇.

If two lines are perpendicular to each other (at right angles), the product of their slopes will be -1. Therefore, their slopes will be negative reciprocals of each other.

Therefore, the slope of the line perpendicular to the given equation is:

$\sf m=\dfrac{7}{5}$

Substitute the found slope and the given point (6, -5) into the slope-intercept formula and solve for b:

$\implies -5=\dfrac{7}{5}(6)+b$

$\implies -5=\dfrac{42}{5}+b$

$\implies b=-\dfrac{67}{5}$

Substitute the found slope and the found value of b into the slope-intercept formula to create the equation for the perpendicular line:

$\implies y=\dfrac{7}{5}x-\dfrac{67}{5}$

Learn more about slope-intercept form here:

brainly.com/question/27317293

brainly.com/question/27926846

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