Answer:
A sample size of 6755 or higher would be appropriate.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error M is given by:
90% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
52% of Independents in the sample opposed the public option.
This means that 
If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?
Sample size of size n or higher when 
. So
A sample size of 6755 or higher would be appropriate.
Answer:
Use a graphing calc or desmos to help guide you.
Step-by-step explanation:
Answer:
8 fits the equation
Step-by-step explanation:
hope this helps
Find the mean of <br>35,26,31,16,21,23,27,30,26,17,19,27
zzz [600]
Hello!
To find the mean, we must add all the terms in the dataset and divide by how many there are.
35+26+31+16+21+23+27+30+26+17+19+27=450
There are 12 terms in the dataset, so we divide by 12:
37.5
So the mean of this set is 37.5.
Hope this helps you!
~Just a joyful teen
Knowing the halfway point (which is 5) helps you so you know wither or not the hundred thousands place goes high or stays the same.
So, for this problem 138,202 would round out to 100,000 because the 3 is below 5 so the hundred thousands place stays the same.
