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Crazy boy [7]
2 years ago
12

How does broad phalanges with claws of tiger and a bear help to adapt in environment?

Physics
1 answer:
Oksanka [162]2 years ago
7 0

Answer:

help to fight against similar predators that compete for limited resources. 

Explanation:

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Astaten whats 2+2 answer
alexandr402 [8]

Answer:

2+2=4

Explanation:

6 0
3 years ago
The density of solid copper is 8960 kg/m3.
Ahat [919]

Explanation:

The density of a solid copper is 8960kg/m^3 while the density of a molten copper is 7900kg/m^3 this is due to the difference in the state of matter, the solid copper is in solid state while the molten copper is in form of a liquid. In the solid copper atoms are tightly pack while they atom are not tightly packed.

3 0
3 years ago
Diffraction gratings with 10,000 lines per centimeter are readily available. Suppose you have one, and you send a beam of white
ArbitrLikvidat [17]

The angles for the first-order diffraction of the shortest and longest wavelengths of visible light are 22.33 ⁰ and 49.46 ⁰ respectively.

<h3>Angle for the first order diffraction</h3>

The angle for the first order diffraction is calculated as follows;

dsinθ = mλ

sinθ = mλ/d

<h3>For shortest wavelength (λ = 380 nm)</h3>

d = 1/10,000 lines/cm

d = 1 x 10⁻⁴ cm x 10⁻² m/cm = 1 x 10⁻⁶ m/lines

sinθ = (1 x 380 x 10⁻⁹)/(1 x 10⁻⁶)

sinθ = 0.38

θ = sin⁻¹(0.38)

θ = 22.33 ⁰

<h3>For longest wavelength (λ = 760 nm)</h3>

sinθ = (1 x 760 x 10⁻⁹)/(1 x 10⁻⁶)

sinθ = 0.76

θ = sin⁻¹(0.76)

θ = 49.46 ⁰

Learn more about diffraction here: brainly.com/question/16749356

#SPJ1

8 0
2 years ago
A 64.1 kg runner has a speed of 3.10 m/s at one instant during a long-distance event.(a) What is the runner's kinetic energy at
Liono4ka [1.6K]

Answer:

(a)  the runner's kinetic energy at the given instant is 308 J

(b)  the kinetic energy increased by a factor of 4.

Explanation:

Given;

mass of the runner, m = 64.1 kg

speed of the runner, u = 3.10 m/s

(a) the kinetic energy of the runner at this instant is calculated as;

K.E_i = \frac{1}{2} mu^2\\\\K.E_i = \frac{1}{2}  \times 64.1 \times 3.1^2\\\\K.E_i = 308 \ J

(b) when the runner doubles his speed, his final kinetic energy is calculated as;

K.E_f = \frac{1}{2} mu_f^2\\\\K.E_f = \frac{1}{2} m(2u)^2\\\\K.E_f = \frac{1}{2} \times 64.1 \ \times (2\times 3.1)^2\\\\K.E_f = 1232 \ J

the change in the kinetic energy is calculated as;

\frac{K.E_f}{K.E_i} = \frac{1232}{308} =4

Thus, the kinetic energy increased by a factor of 4.

4 0
3 years ago
Which action can be explained by physics
Serjik [45]
Walking to school. Hope this helps!
7 0
3 years ago
Read 2 more answers
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