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Cerrena [4.2K]
3 years ago
9

A helicopter is ascending vertically witha speed of 5.40 m/s. At a height of 105 m above the earth a package is dropped from the

helicopter. How much time does is take for the package to reach the ground
Physics
1 answer:
Mrac [35]3 years ago
4 0

Answer: 5.21 s

Explanation:

Given

Helicopter ascends vertically with u=5.4\ m/s

Height of helicopter h=105\ m

When the package leaves the helicopter, it will have the same vertical velocity

Using equation of motion

\Rightarrow h=ut+\dfrac{1}{2}at^2\\\\\Rightarrow 105=-5.4t+0.5\times 9.8t^2\\\Rightarrow 4.9t^2-5.4t-105=0\\\\\Rightarrow t=\dfrac{5.4\pm \sqrt{5.4^2+4\times 4.9\times 105}}{2\times 4.9}\\\\\Rightarrow t=\dfrac{5.4\pm 45.68}{9.8}\\\\\Rightarrow t=5.21\ s\quad \text{Neglect negative value}

So, package will take 5.21 s to reach the ground

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Answer:

B. less

Explanation:

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Weight of an object is given as, W = mg

                                                         

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Answer:

<h2>1.5 ohms</h2>

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