Answer:
208 Joules
Explanation:
The radius of the circular path the charge moves, r = 26 m
The magnetic force acting on the charge particle, F = 16 N
Centripetal force,
= m·v²/r
Kinetic energy, K.E. = (1/2)·m·v²
Where;
m = The mass of the charged particle
v = The velocity of the charged particle
r = The radius of the path of the charged particle
Whereby the magnetic force acting on the charge particle = The centripetal force, we have;
F =
= m·v²/r = 16 N
(1/2) × r ×
= (1/2) × r × m·v²/r = (1/2)·m·v² = K.E.
∴ (1/2) × r ×
= (1/2) × 26 m × 16 N = = (1/2)·m·v² = K.E.
∴ 208 Joules = K.E.
The kinetic energy of an particle moving in the circular path, K.E. = 208 Joules.
Answer:
3WGGRGWERGRG
Explanation:
GERAGAETGAERR GHERUERHGRRGF;SBDF;JKSRDMFNSDFLDGGD;GDVF
Answer:
The longest wavelength for closed at one end and open at the other is
y / 4 where y is the wavelength - that is node - antinode
The next possible wavelength is 3 y / 4 - node - antinode - node -antinode
y / 4 = 3 m y = 12 meters the longest wavelength
3 y / 4 = 3 m y = 4 meters 1 / 3 times as long
Answer:
explained
Explanation:
the Neptune was the first planet discovered through the use of mathematics by two astronomers one French and other English. This was breakthrough success in the field of astronomy that marked the importance of mathematics in astronomy. The discovery of the Neptune resulted from the need to explain the motion of Uranus, motion of which could not be explained by the gravitational effect of Jupiter and Neptune.It needed very complex mathematical equations to be Solved to explain it. The two astronomers were Joseph le Verrier and John Couch Adams.
Answer:
The options are not shown, so i will answer in a general way.
Suppose the case where the forces act in opposite directions, then we need to subtract the forces, and we know that the magnitude of the resultant force will be:
60N - 50N = 10N
Now, suppose the case where both forces act in the exact same direction, in that case, we will add the forces to get:
60N + 50N = 110N
Then the only range of forces that we can get in this system, are the forces such:
10N ≤ F ≤ 110N
Any resultant force outside that range is not possible in this situation.