All categories

2 years ago

An irrational number is one that simply can not be worked into any equation.

Mathematics

1 answer:

Fudgin [204]2 years ago

5 0

Answer:

it can be use in equation

An irrational number is a number that cannot be expressed as a fraction for any integers and. . Irrational numbers have decimal expansions that neither terminate nor become periodic.

You might be interested in

What is 9+6(2^2+4) and why?

Dmitry [639]

Answer:

first : (2^2+4)=(4+4)=8

second : 9+6×8=57

5 0

3 years ago

Read 2 more answers

Write the equation in POINT-SLOPE FORM of the line that passes through the points (4, 0) and (-2, 1).

Neporo4naja [7]

Slope = (1-0)/(-2-4) = -1/6

POINT-SLOPE equation
y - 0 = -1/6(x - 4)

hope it helps

3 0

3 years ago

5(3 – x) + 1 = 3(x+4)

Yuri [45]

Step-by-step explanation:

<h3>✞︎Given</h3>

5(3-x)+1=3(x+4)

Solve Equation

<h3>✞︎Solution</h3>

$\tt\large\underline{15-5x+1=3x+12}$

$\large{✰} \bf \underline\color{purple}{16-5x=3x+12}$

$\tt\large\underline{\longmapsto16-12-3x+5x}$

$\tt\large\underline{\longmapsto4-8x}$

$\tt\large\underline{\longmapsto8x=4}$

$X=\longmapsto\sf \dfrac{\cancel{4}}{\cancel{8}}$

$\tt\large\underline{\longmapsto \: \: \: \: x = \frac{1}{2} }$

3 0

3 years ago

A 5 mile jogging path diagonal divides a rectangular park in half. The park is 4 miles long. Find the width of the park.

levacccp [35]

Answer: The required width of the park is 3 miles.

Step-by-step explanation: Given that a 5 mile jogging path diagonal divides a rectangular park in half and the park is 4 miles long.

We are to find the width of the park.

As shown in the attached figure below, the diagonal BD divides the rectangle ABCD into two equal parts,

where length DA = 5 miles, BD = 4 miles and AB = width = ?

Since each angle of a rectangle is right-angle, so triangle ABD will be a right-angled triangle.

Using Pythagoras theorem in triangle ABD, we have

$BD^2=AB^2+DA^2\\\\\Rightarrow AB=\sqrt{BD^2-DA^2}\\\\\Rightarrow AB=\sqrt{5^2-4^2}\\\\\Rightarrow AB=\sqrt{25-16}\\\\\Rightarrow AB=\sqrt{9}\\\\\Rightarrow AB=3.$

Thus, the required width of the park is 3 miles.

7 0

3 years ago

Abc=3x+5 cbd=2x+5 find the following m

Monica [59]

Sry idk wish I could know but good luck

4 0

3 years ago